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VashaNatasha [74]

3 years ago

12

During a sale at a bookstore, Joseph buys a book at full price. He is given a 50 percent discount on a second book of equal or l

ess value. If Joseph buys two books that have a full price of $15 and $10, by what percent is the total cost of the two books reduced during the sale? (A) 5% (B) 20% (C) 25% (D) 30% (E) 50%

1 answer:

NARA [144]3 years ago

5 0

Total cost of books was 15 + 10 or 25. With the 50 % discount on the $10 book, the total is now $20. The total cost was reduced by (B) 20%.
$5 off the $25 price is a 20% discount.

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A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

3 years ago

Ab^2-4/10 when a=4 b=6

hammer [34]

$\huge\text{Hey there!}$

$\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}$

$\large\boxed{\rm{6^2}}$

$\large\boxed{\rm{= 6 \times6}}$

$\large\boxed{\rm{= \bf 36}}$

$\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}$

$\large\boxed{\rm{4(36)}}$

$\large\boxed{\rm{= \bf 144}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}$

$\large\boxed{\rm{\bold{144} - 4}}$

$\large\boxed{= \rm{\bf 140}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}$

$\large\boxed{\rm{= \bf 14}}$

$\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

4 0

2 years ago

Is (–5, –1) a solution to the equation y = 5x?

Mamont248 [21]

Answer:

-1=5(-5)

-1=-25

nope

Step-by-step explanation:

4 0

3 years ago

Find the area under the standard normal curve between z = −2.57 and z = 1.27. Round your answer to four decimal places, if neces

dexar [7]

P(-2.57 ≤ Z ≤ 1.27) = P(Z ≤ 1.27) - P(Z ≤ -2.57)

P(Z ≤ 1.27) = 0.8980
P(Z ≤ -2.57) = 1 - P(Z ≤ 2.57) = 1 - 0.99488 = 0.00512

P(-2.57 ≤ Z ≤ 1.27) = 0.8980 - 0.00512 = 0.89288
0.8929 (4 d.p.)

4 0

3 years ago

Write 2.1 (periodic decimal, only 1 repeats) as a mixed number. Show your work.

zvonat [6]

Answer:

2 1/10

Step-by-step explanation:

.1 is the same as 1/10 and the 2 is well a normal boring 2

8 0

3 years ago

Read 2 more answers