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Vedmedyk [2.9K]
3 years ago
15

Help solve lowest term of 836/54 please

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0
The lowest term of 836/54 is 418/27!
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Marrrta [24]
Just comparing your (x, y) points to the values on the table, it looks like b) would be the quick answer. Since it states under the table to use average values within each range.
So for x=62 (the weight), we have y=122 (the iron count) which would be the average of the range between 115 and 129.

Similiarly, x=70 corresponds to y=146, which is the average of 139 and 153.
You could take the average values of your highest and lowest iron count ranges compare them to the max-min weight to get your slope. Looks like it would be (155-112)/(73-58)= 43/15= 2.8666 repeating. That would make sense with the slope in the equation listed in b) as well. <span>
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8 0
3 years ago
This is a picture of a square pyramid and the net for the square pyramid. What is the surface area of the square pyramid? 108 ft
Bad White [126]
The answer is 240ft^2. The area of the square base is 64 ft and the area of all four triangles is 176ft.
4 0
3 years ago
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Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How
marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25  

And rounded up we have that n=601

3 0
3 years ago
Which are partial products for 68 × 43?
blagie [28]

Partial products are the products obtained during the intermediate stages in order to complete a multiplication process.

Consider 68 \times 43, we have to determine the partial products in this.

Now, 68 \times 43

Expanding this, we get

(60+8) \times (40+3)

= (60\times 40) +(60 \times 3) + (8 \times 40) + (8 \times 3)

= 2400 + 180 + 320 + 24

= 2924

Hence, 8 \times 40=320 and 8 \times 3 = 24 are the required partial products in the product of 68 and 43.

So, Option 3 and 4 are the correct answers.

3 0
3 years ago
A number went into this machine and 36 came out. What number went in?
labwork [276]

Answer:

6? If its a squared machine than it is 6 bc 6 squared is 36.  sorry if it is wrong.

Step-by-step explanation:

3 0
3 years ago
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