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Zepler [3.9K]
4 years ago
9

Help please ty ty Appreciate it

Mathematics
1 answer:
MAVERICK [17]4 years ago
6 0

Answer:

a. 113.1 cm^3.

b. 339.29 cm^3.

c. 18 cm.

d. 508.94 cm^3.

e. 169.65 cm^3.

Step-by-step explanation:

a. (4/3) * pi * (3^3) = (4/3) * pi * 27 = 36 * pi = 113.0973355, which is about 113.1 cm^{3}.

b. 113.0973355 * 3 = 339.2920066, which is about 339.29 cm^3.

c. Since the radius of a tennis ball is 3 cm, the diameter is 6 cm. There are three tennis balls, and the diameters added up become the height of the cylinder. 6 + 6 + 6 = 18 cm.

d. pi * (3^2) * 18 = pi * 9 * 18 = pi * 162 = 508.9380099, which is about 508.94 cm^3.

e. 508.9380099 - 339.2920066 = 169.6460033, which is about 169.65 cm^3.

Hope this helps!!

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ycow [4]

Answer:

9/11

Step-by-step explanation:

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5 0
3 years ago
A collection of nickels and dimes is worth $9.45. If the number of dimes is doubled, the value is
eduard

Answer:

The number of nickels is 45 and the number of dimes is 72.

Step-by-step explanation:

Let

x ----> number of nickels

y ----> number of dimes

Remember that

1\ nickel=\$0.05

1\ dime=\$0.10

so

0.05x+0.10y=9.45 ------> equation A

0.05x+0.10(2y)=16.65

0.05x+0.20y=16.65 ------> equation B

<em>Solve the system by substitution</em>

we have

0.05x+0.10y=9.45 ------> equation A

0.05x+0.20y=16.65 ------> equation B

Multiply both equations by 100 both sides

5x+10y=945 ---->5x=945-10y --> equation C

5x+20y=1,665 ----> equation D

substitute equation C in equation D

(945-10y)+20y=1,665

solve for y

945+10y=1,665

10y=1,665-945

10y=720

y=72\ dimes

Find the value of x

5x=945-10y

5x=945-10(72)

5x=225

x=45\ nickels

<em>Alternative Method</em>

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

the solution is the point (45,72)

therefore

The number of nickels is 45 and the number of dimes is 72.

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Hi! Can you try sending a picture of the figure that this is referring to, so I can try answering the question?
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  • you will need 2 busses to only transport the boys.
  • Mark is at (1 + 5/6) miles of his house.
<h3>How many buses would it take to carry only the boys?</h3>

We know that there are (3 + 1/2) groups, such that each group fill one bus.

2/5 of the students are boys, then the number of groups that we can make only with boys is:

(2/5)*(3 + 1/2) = 6/5 + 1/5 = 7/5 = 5/5 + 2/5 = 1 + 2/5

Then you can make one and a little less than a half of a group, which means that you need 1 and 2/5 of a buss to transport the boys, rounding that to the a whole number, you will need 2 busses to only transport the boys.

<h3>How far is Mark from his house?</h3>

The original distance is:

D = (2 + 3/4) miles.

But Mark only covers 2/3 of that distance, then we have:

d = (2/3)*D = (2/3)*(2 + 3/4) miles = (4/3 + 2/4) miles

d = (4/3 + 1/2) miles = (8/6 + 3/6) miles = (1 + 5/6) miles

Mark is at (1 + 5/6) miles of his house.

If you want to learn more about mixed numbers:

brainly.com/question/21610929

#SPJ1

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Answer:

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