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Greeley [361]
3 years ago
10

600% as a decimal and fraction or mixed number

Mathematics
2 answers:
OleMash [197]3 years ago
8 0
Hello there!

Decimal

To convert a percentage to decimal, you move the decimal point 2 places to the left. 600% - 6.0

Fraction
To convert a percentage to a fraction, divide the percentage by 100. 600/100 = 6/1 = 6

Hope this helps! :)
Nookie1986 [14]3 years ago
6 0

Answer:

600% can be written as  6.0 as decimal and 6/1 as a fraction

Step-by-step explanation:

600% as a decimal and fraction or mixed number

To remove % we always divide by 100

600% is 600 divide by 100

\frac{600}{100} =6

6 can be written as decimal as 6.0

6 can be written as a fraction as 6/1

600% can be written as  6.0 as decimal and 6/1 as a fraction

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The baby giraffe weighed 132 pounds at birth. He gained weight at a steady rate for the first 7 months until his weight reached
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Step-by-step explanation:

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Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
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Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

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Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p
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Answer:

A)

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>B)</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em> Rejected H₀</em>

<em>There is a significant difference in drug resistance between the two states.</em>

C)

P - value = 0.0066

<em>P - value = 0.0066 < 0.02</em>

<em>D) </em>

<em>1) Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first sample size n₁ = 174</em>

Suppose that, of 174 cases tested in a certain state, 11 were found to be drug-resistant.

<em>First sample proportion </em>

                    p_{1} = \frac{x_{1} }{n_{1} } = \frac{11}{174} = 0.0632

<em>Given second sample size n₂ = 375</em>

Given data  Suppose also that, of 375 cases tested in another state, 7 were found to be drug-resistant

<em>Second sample proportion</em>

<em>                  </em>p_{2} = \frac{x_{2} }{n_{2} } = \frac{7}{375} = 0.0186<em></em>

<u><em>Step(ii):-</em></u>

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>        Where </em>

<em>         </em>P = \frac{n_{1}p_{1} +n_{2} p_{2}  }{n_{1} +n_{2} }<em></em>

<em>        </em>P = \frac{174 (0.0632) + 375 (0.0186) }{174+375 } =  \frac{17.9718}{549} = 0.0327<em></em>

<em>       Q = 1 - P = 1 - 0.0327 = 0.9673</em>

<u><em>Step(iii):-</em></u>

<em></em>

<em>  Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>          </em>Z = \frac{0.0632-0.0186  }{\sqrt{0.0327 X 0.9673(\frac{1}{174 }+\frac{1}{375 } ) } }<em></em>

<em>       Z  =   2.7261</em>

<em>   </em>

<em>Level of significance = 0.02 or 0.98</em>

<em>The z-value = 2.054</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em>    Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

 <u><em>P- value </em></u>

<em>P( Z > 2.7261) = 1 - P( Z < 2.726)</em>

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<em>                         = 0.5 - 0.4967</em>

<em>                          = 0.0033</em>

we will use two tailed test

<em>2 P( Z > 2.7261)  = 2 × 0.0033</em>

<em>                            = 0.0066</em>

<em>P - value = 0.0066 < 0.02</em>

<em>  Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

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