The junction where one neuron can transfer an impulse to the next structure is known as a

What is likely to happen if we can't control our experiment properly? A. Our hypothesis will have to be changed. B. We will need

REY [17]

The answer to your question
is b

4 0

3 years ago

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Identify the reversible chemical reaction below. A. reactants=>products B. Products <=> reactants C. products => rea

Korvikt [17]

Answer:

Its B

Explanation:

Products <=> reactants; products can go back to reactant and reactants can form products, depending on the equilibrium position.

The equilibrium position, if it is on the left, and much of the product is formed. If the equilibrium position is not the right, then its the vice versa The equilibrium position is determined by ;

Temperature

If the reaction is endothermic, it will be favoured by increase in temperature and equilibrium position will shift to the right ( reactants )

If the reaction is exothermic, its the vice versa

NOTE: Only temperature affects the equilibrium position

5 0

3 years ago

True or False, Substances have different properties?

4vir4ik [10]

True.....................................

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3 years ago

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You are a chemist working in your laboratory. In your storage closet you have a

Nastasia [14]

Ans is B.Bromine. Only two elements are liquid at room temperature ( mercury and Bromine) . Helium and chlorine, arsenic are gases.

8 0

3 years ago

Imagine that you have a 5.00 L gas tank and a 3.50 L gas tank. You need to fill one tank with oxygen and the other with acetylen

Lorico [155]

Answer:

77.14 atm of pressure should be of an acetylene in the tank.

Explanation:

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.

Moles of oxygen= $n_1$

Moles of acetylene = $n_2$

$\frac{n_1}{n_2}=\frac{5 mol}{2 mol}=\frac{5}{2}$

Volume of large tank with oxygen gas, $V_1 = 5.00 L$

Pressure of the oxygen gas inside the tank = $P_1=135 atm$

$RT=\frac{P_1V_1}{n_1}$ ..[1]

Volume of small tank with acetylene gas , $V_2= 3.50 L$

Pressure of the acetylene gas inside the tank = $P_2=?$

$RT=\frac{P_2V_1}{n_2}$ ..[2]

Considering both the gases having same temperature T, [1]=[2]

$\frac{P_1V_1}{n_1}=\frac{P_2V_2}{n_2}$

$P_2=\frac{P_1V_1\times n_2}{V_2\times n_1}$

$=\frac{135 atm\times 5.00 L\times 2}{3.50 L\times 5}=77.14 atm$

77.14 atm of pressure should be of an acetylene in the tank.

8 0

3 years ago