NAD serves as the bulk of the oxidative processes in the citric acid cycle's initial electron acceptor.
<h3>What are
electron acceptors in c
itric acid cycle?</h3>
- In the Krebs cycle, which transfers electrons via the electron transport chain with oxygen as the final acceptor, coenzymes like FAD and NAD+ are reduced.
- In a single cycle, three NADH+ and one FADH2 are produced, and when the cycle enters the electron transport chain, 10 ATP is produced.
- The final electron acceptor in the electron transport chain is oxygen. The proton gradient in the intermembrane gap is produced by NADH molecules donating electrons that are then transmitted through a number of different proteins.
<h3>What occurs throughout the citric acid cycle?</h3>
The cycle of citric acid: In the citric acid cycle, a six-carbon citrate molecule is created when an acetyl group from acetyl CoA is joined to a four-carbon oxaloacetate molecule.
Citrate is oxidized over a number of steps, generating two molecules of carbon dioxide for each acetyl group added to the cycle.
learn more about citric acid cycle here
<u>brainly.com/question/14900762</u>
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Answer:
1s2 2s2 2p3
Explanation:
we know that the number of electrons in an atom is equal to number of protons. So the number of electrons here is 7.
Using Moller chart, the electronic configuration is writen by the electrons first enterring into 1s then into 2s after 2p. The s orbital accomodates maximum of 2 electrons.
∴ for atomic no. 7 nitrogen atom, electronic configuration is 1s2 2s2 2p3.
Answer:
oof idk I would suggest looking at an example and try going off that
Answer:
1134
Explanation:
(the ones place was rounded up). 1133.981 is the unrounded answer.
Answer:
19.12 L
Explanation:
At STP(i.e. Standard temperature and pressure).
The volume occupied by one mole of gas = 22.4 L
The pressure = 1 atm
The temperature = 273 K
Thus, since 1 mole of gas = 22.4 L;
Then 0.853 moles of N2 gas will occupy:
= (0.853 moles of N2 gas × 22.4 L)/ 1 mole of N2 gas
= 19.12 L
