1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodomira [7]
3 years ago
13

What volume in milliters would give 12.0 grams of NaOH from a 2.0 M NaOH solution?

Chemistry
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:

V = 150 mL

Explanation:

Hello!

In this case, since the molarity of a solution is computed via:

M=\frac{n}{V}

Whereas we are asked to compute the volume:

V=\frac{n}{M}

Thus, we first compute the moles in 12.0 g of NaOH as its molar mass is about 40.0 g/mol:

n=\frac{12.0g}{40.0g/mol}=0.3mol

Thus, at first instance, the volume liters is:

V=\frac{0.3mol}{2.0mol/L} \\\\V=0.15L

Which in milliliters is:

V=0.15L*\frac{1000mL}{1L}\\\\V=150mL

Best regards!

You might be interested in
What mass of aluminum is needed to produce 0.500 mole of aluminum chloride?
3241004551 [841]

Answer:  " 13.5 g Al " ;

                    →  that is:  "13.5 grams of aluminum."

<u>____________________________</u>

Explanation:

<u>____________________________</u>

<u>Note</u>: What is missing from the question is the "balanced chemical equation" for the "chemical reaction" that contains:

 The reactants:  "aluminum (Al) " ;  and "chlorine (Cl) " ;  and:

 The product:    "aluminum choloride (AlCl₃) " .

____________________________

The "balanced chemical equation" is:

____________________________

        2 Al   +   3 Cl₂   →   2 AlCl₃   ;

_____________________________

<u>Note</u>: The molecular weight of "aluminum (Al)" is:   " 26.98 g /mol " .

____________________________

So:  We call solve using a technique known as:  "dimensional analysis" :

____________________________

  0.500 mol AlCl₃ * (\frac{2mol Al}{2mol AlCl_{3} }) * (\frac{26.98g Al}{1 mol Al}) = ?

____________________________

<u>Note</u>:  The units of "mol AlCl₃" cancel out to "1' ; and:

          The  units of "mol Al" cancel out to "1" ; and we are left with:

____________________________

 " \frac{(0.500 * 2 * 26.98)}{2}   g Al ["grams of aluminum"] ;

____________________________

<u>Note</u>: We can "cancel out the "2's" ; since "2/2 = 1 " ; and we have:

 →  (0.500 * 26.98) g Al ;

    = 13.49 g Al ;

         →  Round to 3 (Three) significant figures;

         →  Since:  "0.500" has 3 (Three) significant figures:

____________________________

   =  13.5 g Al ; that is:  "13.5 grams of aluminum."

____________________________

 Hope this is helpful!  

      Best wishes to you in your academic pursuits—and within the "Brainly" community!

____________________________

3 0
3 years ago
How much power is used if a force of 54 newtons is used to pull a wagon a distance of 10 meters in 6 seconds? 3,240 W 90 W 32.4
timama [110]
Power is defined in a mathematical expression as P = F x v where F is in N and v is in m/s. From the given equation, the v = d/t which is v = 10/ 6, then substituting the answer to the power formula W = 54 N (10/6 m/s) = 90 Watts. 
3 0
3 years ago
Read 2 more answers
Carbon 14 has a half-life of 5730 years. A geologist has dated a fossil sample, at roughly 28650 years. How much carbon 14 remai
IgorC [24]
<h3>Answer </h3>

After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left. after three half lives or 17190 years, 8.75 g of C-14 will be

Explanation:

hope this help

7 0
2 years ago
How many grams of carbon are contained in 2.25 g of potassium carbonate, K2CO3
romanna [79]

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

<h3>Molecular mass of potassium carbonate</h3>

The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;

M = K₂CO₃

M = (39 x 2) + (12) + (16 x 3)

M = 138 g

mass of carbon in potassium carbonate, K₂CO₃ is = 12 g

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;

138 g ------------ 12 g of carbon

2.25 g ------------ ?

= (2.25 x 12) / 138

= 0.196 g

Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

Learn more about potassium carbonate here: brainly.com/question/27514966

#SPJ1

5 0
1 year ago
Which quantity is equivalent to the product of the absolute index of refraction of water and the speed of light in water?
givi [52]

The quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

<h3>What is the speed of light?</h3>

Speed of light is the rate of speed though the light travels. To find the speed of light in any medium, the following formula is used.

v=\dfrac{c}{n}

Here, (n) is the index of reaction and (c) is the speed of light in the vacuum. The speed of light in the vacuum is almost equal to the 3.0×10⁸ m/s.

Now the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water has to be find out.

The above formula can be written as,

v=\dfrac{c}{n}\\vn=c\\c=vn

Here, the product of index of refraction and speed of light is equal to the speed of light in vacuum. This will be true for water as well.

Thus, the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

Learn more about the speed of light here;

brainly.com/question/104425

#SPJ4

3 0
1 year ago
Other questions:
  • What is the molarity of a solution containing 23 g of NaCl in 500 mL of solution?
    14·1 answer
  • Litmus paper can be used to determine the _______ of a substance.
    12·1 answer
  • If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p
    5·1 answer
  • According to Kirchhoff’s third law, when light from a blackbody having a continuous spectrum passes through a cool transparent g
    13·1 answer
  • Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c
    11·2 answers
  • 2)
    14·1 answer
  • Ed records the temperature of two pots of water. Pot X has a temperature of 56 degrees Fahrenheit, and pot Y has a temperature o
    8·2 answers
  • There are 235.5 grams of Calcium chloride dissolved in 2.5 liters of solution. What is the molarity of
    12·1 answer
  • Cassidee walks 1-mile north and then turns and walks 2 miles west. Distance Displacement
    9·1 answer
  • Write the general electron configuration of a transition element(b) in Period 6.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!