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Ilia_Sergeevich [38]
3 years ago
5

An unknown solid acid has a formula h2x. How could you determine the molar mass of the unknown acid for a titration with 0.455 m

koh using phenolphthalein indicator?
Chemistry
1 answer:
Goshia [24]3 years ago
3 0

Answer:

The answer is in the explanation.

Explanation:

A titration of H₂X with KOH produce:

H₂X + 2KOH → 2H₂O + K₂X

It is possible to obtain the moles of H₂X because the moles of KOH are the spent volume of the titration in liters × 0,455M. As for a complete titration of H₂X moles you need twice moles of KOH you know the moles of KOH obtained are half H₂X moles.

As you know the mass of the solid acid that you titrate and molar mass of acid is:

mass of acid / moles of acid. You can determine the molar mass of the unknown acid.

I hope it helps!

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Yanka [14]

Answer:

\Delta _rH=17.51\frac{kJ}{mol}

Explanation:

Hello!

In this case, since the enthalpy change for any process is computed by subtracting the enthalpy of the final state and the enthalpy of the initial state, for the given phase change, we subtract the enthalpy of the liquid (final state) and the enthalpy of the solid (initial state) considering this a melting process:

\Delta _rH=-390.76\frac{kJ}{mol} -(-408.27\frac{kJ}{mol} )\\\\\Delta _rH=17.51\frac{kJ}{mol}

Which makes sense because this process absorbs energy.

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5 0
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Answer:

5.62 g of F2

Explanation:

We have to start with the chemical reaction:

Cl_2~+~3F_2~-->~2ClF_3

<u>We have a balanced reaction</u>, so we can continue with the <u>mol calculation</u>. For this, we need to know the <u>molar mass</u> of Cl_2  (70.906 g/mol), so:

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Now, with the <u>molar ratio</u> between Cl_2  and F_2  we can convert from moles of Cl_2  and F_2  (1:3), so:

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Finally, with the <u>molar mass</u> of F_2 we can calculate the gram of F_2 (37.99 g/mol), so:

0.148~mol~F_2\frac{37.99~g~F_2}{1~mol~F_2}=5.62~g~F_2

I hope it helps!

8 0
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