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lions [1.4K]
4 years ago
5

If you know that a population is 75% the dominant phenotype and 25% is the recessive phenotype, can you determine approximately

how many of the dominant phenotype are homozygous dominant and how many are heterozygous dominant? Try this mathematically
Biology
1 answer:
Andreyy894 years ago
8 0
If dominant allele = p, and recessive allele = q,
and p+q = 1, then:
{(p + q)}^{2}  =  {p}^{2}  + 2pq +  {q}^{2}  \\ where \:  {p}^{2}  \: is \: homozygous \: domin \\  {q}^{2}  \: is \: homozygous \: recessive \\ and \: 2pq = heterozygous
So if 75% have the p, then p^2 = homozygous dominant
{p}^{2}  =  {(.75)}^{2}  = .5625
And if the other 25% have the q, the q^2 = homozygous recessive
{q}^{2}  =  {(.25)}^{2}  = .0625
Now those remaining MUST be the heterozygous, thus 2pq are those:
2pq = 2(.75)(.25) = .375

Therefore homozygous dominant are 56.3% and heterozygous are 37.5%
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