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krok68 [10]
2 years ago
5

An object is released from rest and falls a distance h during the first second of time. How far will it fall during the next sec

ond of time? Explain.
a. 2h
b. 4h
c. h
d. h^2
e. 3h
Physics
1 answer:
Viefleur [7K]2 years ago
3 0

Answer:

E. 3h

Explanation:

We know that

u = 0 m/s.

velocity after t = 1s

v = u+gt = 0+9.81 x 1s= 9.81 m/s

distance covered in 1st sec

= =>> ut+0.5 x g x t²

=>>0 + 0.5x 9.81 x 1 = 4.90m

Let 4.90 be h

distance travelled in 2nd second will now be used

So velocity after t = 1s

=>>1 x t+ 0.5 x g x t²

=>9.81x 1 + 0.5 x 9.81 x 1 = 3 x 4.90

So since h= 4.90

Then the ans is 3x h = 3h

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Answer:

a. at either A or B

Explanation:

Kinetic energy may be defined as the energy of the system or an object which is due to its velocity of the object it possess.

In the context, an object having mass  is attached to spring which is vertical and the object moves up and down due to spring effect between points A and B. Now these points A and B are the extreme points after which the object bounces back.

At point A and B, the velocity of the object becomes zero and hence the kinetic energy of a body varies directly proportional to its velocity.

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Answer:

a

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b

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The explanation is shown in the first and second uploaded image

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2 years ago
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Afina-wow [57]
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3 years ago
If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?
REY [17]

Answer:

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Explanation:

Angular velocity is usually measured with \frac{radians}{sec}, so I'm going to use that to answer your question.

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Using the values from the question, we get:

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Hope this helped!

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