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Anarel [89]
3 years ago
13

A dog of mass 4 kg runs up a hill of height 8 m. How much gravitational potential energy does the dog gain?

Physics
2 answers:
Genrish500 [490]3 years ago
8 0
A. 314 because when you use the formula for the GPE ; GPE=MGH or means mass times gravity time height (4x8x9.8) and thats equivalent to 313.6 which rounds up to 314. Hope it helps 
Scrat [10]3 years ago
6 0

Answer:

The gravitational potential energy is 314 J.

(A) is correct option.

Explanation:  

Given that,

Mass of dog = 4 kg

Height = 8 m

We need to calculate the potential energy

Using formula of potential energy

P.E = mgh

m = mass

g = acceleration due to gravity

h = height

Put the value into the formula

P.E=4\times9.8\times8

P.E=313.6=314\ J

Hence, The gravitational potential energy is 314 J.

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Kelly's mother is taking her temperature to see if she has a fever. Which unit of measurement could be used to measure Kelly's b
Sergeeva-Olga [200]

Answer:

The answer is A.

Explanation:

To measure a temperature, you have degrees with Farenheight or Celsius. Meters are measured with a meter stick while grams and kilograms are measurments for weight.

Therefore, degrees Celsius is your answer.

Best of Luck to you!

7 0
3 years ago
Read 2 more answers
A 420-turn circular coil with an area of 0.0650 m2 is mounted on a rotating frame, which turns at a rate of 22.3 rad/s in the pr
Ivenika [448]

Answer:

33.48 V

Explanation:

Parameters given:

Number of turns, N = 420

Magnetic field strength, B = 0.055 T

Area, A = 0.065 m²

Angular velocity, ω = 22.3 rad/s

EMF induced in a coil is given as:

EMF = -dΦ/dt

where Φ = magnetic flux

Magnetic flux, Φ, is given as:

Φ = B * N * A * cosωt

EMF = -d( B * N * A * cosωt) / dt

EMF = B * N * A * ω * sinωt

where ωt = 90°

Therefore:

EMF = 0.055 * 420 * 0.065 * 22.3 * sin90°

EMF = 33.48 V

7 0
3 years ago
The journey of an electron through an external circuit involves a long and slow zigzag path that is characterized by losses in e
Kitty [74]

Answer:

d_{b} = 2 d_{a}

Explanation:

The electrical resistance for a cylindrical wire is described by the expression

         R = ρ L / A

The area of ​​a circle is

     A = π r²

     r = d / 2

     A = π d²/4

We substitute

      R = ρ L  4 /π d²

Let's apply this expression to our case, they indicate that the resistance of wire A is 4 times the resistance of wire B

    R_{a} = 4 R_{b}

We substitute

    ρ  4/π d_{a}² = 4 (ρ  4/π d_{b}²)

    1 / d_{a}² = 4 / d_{b}²

     d_{a} = d_{b} / 2

4 0
3 years ago
Derive the formula 2as=v² -u² where the formula have have usual meanings
attashe74 [19]

Answer:The main formula is v² = u² + 2as

Explanation:

S=½(u +v)t

t = v+u/a

S=½(v-u)(v+u/a)

S=½v²+uv-uv-u²/a

2as=v²-u²

5 0
3 years ago
How fast does a 2 MeV fission neutron travel through a reactor core?
Artemon [7]

Answer:

The answer is 1.956 \times 10^7\ m/s

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy E = mc^2, so the definition of energy in this case is

E = \frac{1}{2}m v^2.

From the last equation,

v= \sqrt{2E/m}

where

E = 2 MeV = 3.204 \times 10^{-13} J

and the mass of the neutron is

m = 1.675\times 10^{-27}\ Kg.

Then

v = 1.956 \times 10^7\ m/s

the equivalent of 0.065 the speed of light.

5 0
3 years ago
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