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3 years ago

A dog of mass 4 kg runs up a hill of height 8 m. How much gravitational potential energy does the dog gain?

2 answers:

8 0

A. 314 because when you use the formula for the GPE ; GPE=MGH or means mass times gravity time height (4x8x9.8) and thats equivalent to 313.6 which rounds up to 314. Hope it helps

Scrat [10]3 years ago

6 0

Answer:

The gravitational potential energy is 314 J.

(A) is correct option.

Explanation:

Given that,

Mass of dog = 4 kg

Height = 8 m

We need to calculate the potential energy

Using formula of potential energy

$P.E = mgh$

m = mass

g = acceleration due to gravity

h = height

Put the value into the formula

$P.E=4\times9.8\times8$

$P.E=313.6=314\ J$

Hence, The gravitational potential energy is 314 J.

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Two objects that are not initially in thermal equilibrium are placed in close contact. After a while, the temperature of the cod

Dima020 [189]

Answer:

If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops, then the specific heats of both objects will be equal.

Explanation:

If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops when the two objects of same mass are brought into contact, then their specific heat capacity is equal.

We can prove this by the equation of heat for the two bodies:

According to given condition,

$\Delta T_1=\Delta T_2$

$\frac{Q_1}{m_1.c_1} = \frac{Q_2}{m_2.c_2}$

when there is no heat loss from the system of two bodies then $Q_1=Q_2$

$\frac{1}{m.c_1} =\frac{1}{m.c_2}$

$\Rightarrow c_1=c_2$

Thermal conductivity is ultimately affects the rate of heat transfer, however the bodies will attain their final temperature based upon their mass and their specific heat capacities.

The temperature of the colder object will rise twice as much as the temperature of the hotter object only in two cases:

when the specific heat of the colder object is half the specific heat of the hotter object while mass is equal for both.

the mass of colder object is half the mass of the hotter object while their specific heat is same.

3 0

3 years ago

Can someone help me with 1-2

ira [324]

Can't really plot a graph here for question 1.

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b) From the graph, at 10 seconds, the car is moving at 20 m/s.

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3 years ago

What is the mass of a cylinder of lead that is 1.80 in in diameter, and 4.12 in long. the density of lead is 11.4 g/ml?

Sedbober [7]

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3 years ago

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On your first trip to Planet X you happen to take along a 180 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r

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Answer:

g_x = 3.0 m / s^2

Explanation:

Given:

- Change in length of spring [email protected] = 22.6 cm

- Time taken for 11 oscillations t = 19.0 s

Find:

- The value of gravitational free fall g_x at plant X:

Solution:

- We will assume a simple harmonic motion of the mass for which Time is:

T = 2*pi*sqrt(k / m ) ...... 1

- Sum of forces in vertical direction @equilibrium is zero:

F_net = k*x - m*g_x = 0

(k / m) = (g_x / x) .... 2

- substitute Eq 2 into Eq 1:

2*pi / T = sqrt ( g_x / x )

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g_x = (2*pi / (19 / 11) )^2 * 0.226

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3 years ago

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