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3 years ago

What is the weight, in pounds, of a 205-kg object on jupiter?

1 answer:

4 0

a 205 kg mass object will weight 1143.43 lbs on Jupiter. Looking up the surface gravity of Jupiter, you can find that it's 2.53 times that of earth. So the 205 kg object will weigh 205 * 2.53 = 518.65 kg on Jupiter. Now we need to convert from kg to pounds. This is done by multiplying by 2.20462 518.65 kg * 2.20462 lb/kg = 1143.43 lb

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Physics and chemistry is the study of what?

LenKa [72]

<h3>physical science deals with the study of physics chemistry</h3>

Explanation:

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3 years ago

Do electric lights in some electronic devices change electricity into motion

Phantasy [73]

Answer:

A generator converts mechanical energy into electrical energy, while a motor does the opposite - it converts electrical energy into mechanical energy. Both devices work because of electromagnetic induction, which is when a voltage is induced by a changing magnetic field....

Explanation:

I hope this helps with what you were looking for!!!

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4 years ago

If a 2 kg object is falling at 3 m/s at what rate is gravity working on the object

777dan777 [17]

Answer:

+9.8m/s^2

Explanation:

The rate of gravity of the object is constant thriughout the surface of the earth.

For falling object, the rate of gravity is positive since the body is coming down (falling)

The rate of gravity is negative if the body is going up

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Since the object is falling, hence the acceleration due to gravity is positive.

Rate of gravity working on the object will be +9.8m/s^2

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3 years ago

Which one of the following is a decomposition reaction?

horsena [70]

It would be A because Decomposition is when a substance breaks down into two.

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3 years ago

Read 2 more answers

Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su

dybincka [34]

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
La longitud de onda de las ondas sonoras es 1,470 metros.

1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ( $v$ ), en metros por segundo:

$v = \sqrt{\frac{K}{\rho} }$ (1)

Donde:

$K$ - Módulo de compresibilidad, en newtons por metro cuadrado.
$\rho$ - Densidad del agua, en kilogramos por metro cúbico.

Si sabemos que $\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}$ y $K = 2,16\times 10^{9}\,\frac{N}{m^{2}}$ , entonces la velocidad de las ondas sonoras es:

$v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }$

$v\approx 1469,694\,\frac{m}{s}$

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

2) Luego, determinamos la longitud de onda ( $\lambda$ ), en metros, mediante la siguiente fórmula:

$\lambda = \frac{v}{f}$ (2)

Donde $f$ es la frecuencia de las ondas sonoras, en hertz.

Si sabemos que $v\approx 1469,694\,\frac{m}{s}$ y $f = 1000\,hz$ , entonces la longitud de onda de las ondas sonoras es:

$\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}$

$\lambda = 1,470\,m$

La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: brainly.com/question/1070238

6 0

2 years ago