Answer:
I think C......................
The velocity of shortening refers to the speed of the contraction from
the muscle shortening while lifting a load. The relationship between the
resistance and velocity of shortening is inverse. The greater the
resistance, the shorter the velocity of shortening and the smaller the
resistance, the larger the velocity of shortening.
Hopefully this help :)
the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period
Thank you
Answer:
0.426 L
Explanation:
Boyles law is expressed as p1v1=p2v2 where
P1 is first pressure, v1 is first volume
P2 is second pressure, v2 is second volume.
Given information
P1=96 kPa, v1=0.45 l
P2=101.3 kpa
Unknown is v2
Making v2 the subject from Boyle's law
Substituting the given values then
Therefore, the volume is approximately 0.426 L
<span>The ball clears by 11.79 meters
Let's first determine the horizontal and vertical velocities of the ball.
h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s
v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s
Now determine how many seconds it will take for the ball to get to the goal.
t = 36.0 m / 15.04 m/s = 2.394 s
The height the ball will be at time T is
h = vT - 1/2 A T^2
where
h = height of ball
v = initial vertical velocity
T = time
A = acceleration due to gravity
So plugging into the formula the known values
h = vT - 1/2 A T^2
h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2
h = 42.92 m - 4.9 m/s^2 * 5.731 s^2
h = 42.92 m - 28.0819 m
h = 14.84 m
Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m</span>
