For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
Answer:
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