Answer:
Option 4, 64 cm^2
Step-by-step explanation:
The polygon in the shape of a star can be made to be easier to find the area of by cutting it into triangle. For all the "point edges" of the star, we can cut them in half from the vertex to create two right-angled triangles at each edge. 
The formula of the area of a triangle is bh/2: the height is given as 6cm, the base is 4cm /2 (after you cut it in half) and so is 2 cm. Since the edges can be cut into two, there are 8 right angled triangles at the edges in total. 
To find the area of them:
A=8(bh/2)=8(2*6/2)=48 cm^2
However, we are still missing the part at the centre we haven't found the area of, the square. The area of a square is given by the square of the side length(4cm). Thus, A=4*4=16cm^2
Adding the areas of all the edges and the square:
48 + 16 = 64cm^2
Hence, the area of the polygon is 64cm^2
 
        
                    
             
        
        
        
714, because the unit rate is three and three times 328 is 714
        
                    
             
        
        
        
Answer:
Step-by-step explanation:a/
slope m = [f(x)-f(3)]/(x-3)
b/
tangent y - f(3) = [lim m ,as x-->3](x-3)
 
        
             
        
        
        
Concept: Solution of the given attachment is based on the addition of two vectors as given below.
Consider two vectors P and Q, then resultant of these two vectors is given as, 
 R = P + Q
To find the addition of G & H vectors. That is G + H =?
In the given figure;
Vector A = - Vector G because both are in opposite directions -----(i)
From the figure, 
A + H = F --------------- using the given concept ---------(ii)
Now, shall replace the value of A  from equation (i) in equation(ii)
 - G + H = F
or, G + (- H) = - F
Since the vector addition of G & H is not equal to F.
Hence, the given statement G + H = F is False.