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slavikrds [6]
3 years ago
12

Help with this proof

Mathematics
1 answer:
musickatia [10]3 years ago
6 0
AD = DB

Angle ADE = Angle CDB

Angle DAE = Angle DBC (Alternate angles)

Angle DEA = Angle DCB (Alternate angles)

Since you have two congruent angles and one congruent side, triangle ADE is congruent to triangle CDB. This means that DE is congruent to DC implying D is the midpoint of CE.
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staci has seven more cats than Talyor. write an expression that illustrates how many cats staci has. use x to represent the numb
belka [17]
X = 7 + staci  since 7 more cats added to x is stacis amount
7 0
3 years ago
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5/6 divided by 2 1/6
Gekata [30.6K]

Answer:

5/39

Step-by-step explanation:

2 1/6 = 13/2

5/6 divided by 13/2 = 5/6 multiplied by 2/13

5/6(2/13) = 5/39

so, your answer is 5/39

4 0
3 years ago
Roman buys seed packets for the school garden. One packet of radish seeds costs $1.75. One packet of tomato seeds costs $2.50. L
HACTEHA [7]
Answer:

C. t=23,r=9 .

Step-by-step explanation:

Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.

Roman spent $62.75

This implies that,

1.75r+2.5t=62.75...eqn1

Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.

This implies that,

r+t=32...eqn2

Using guess and check means we substitute into the given equation.

A) We substitute t=8,r=24 into both equations.

1.75(8)+2.5(24)=62.75...eqn1

14+60\ne 62.75...eqn1

8+24=32...eqn2

Both equations are not satisfied.

B)

We substitute t=9,r=23 into both equations.

1.75(9)+2.5(23)=62.75...eqn1

15.75+57.5\ne 62.75...eqn1

9+23=32...eqn2

Both equations are not satisfied.

C)

We substitute t=23,r=9 into both equations.

1.75(23)+2.5(9)=62.75...eqn1

40.25+22.5 =62.75...eqn1

23+9=32...eqn2

Both equations are satisfied.

Hence the solution is,

t=23,r=9

D) We substitute t=24,r=8 into both equations.

1.75(24)+2.5(8)=62.75...eqn1

42+20\ne 62.75...eqn1

24+8=32...eqn2

Both equations are not satisfied.
4 0
4 years ago
Read 2 more answers
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Table 2 heheheheheehehehehheheheheehheheheheheheheehehehehhehehehehhehehehehehe
6 0
3 years ago
In a class of 7, there are 4 students who play soccer.
borishaifa [10]

the probability of choosing a student who plays soccer is 57%meanwhile the chance of picking a non soccer player is 43%.

8 0
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