Scale drawing to find an area of 6.5 inches and 5 inches

31 km<br>9 km find the area of the triangle <br>

matrenka [14]

What happens to the number after the subtraction sign in each problem

7 0

3 years ago

What do you multiple 24 with to get 120

ohaa [14]

Answer:

5

Step-by-step explanation:

I divided $\frac{120}{24}$ = 5

3 0

3 years ago

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Hey guys please help me out. Math isn't exactly my strong subject and I'd really appreciate this answer with steps. Thank you in

mash [69]

B1 = 2
b2 = (b1)^2 + 1 = 2^2 + 1 = 5
b3 = (b2)^2 + 1 = 5^2 + 1 = 26

b4 = (b3)^2 + 1 = 26^2 + 1 = 676+1=<span>677</span>

8 0

3 years ago

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The area of a rectangle knitted blanket is 9x^2-6x-8. What are the possible dimensions of the blanket? Use factoring

Ilya [14]

Answer:

(3x-4) by (3x+2) or (-3x+4) by (-3x-2)

Step-by-step explanation:

To factor 9x^2-6x-8 we want to find the factors of 9 and the factors of -8 that when multiplied in sequence and then added give us -6.

factors of -8:

-8 & 1

8 & -1

-4 & 2

4 & -2

you might also want to remember that these can be flipped, so if you have -8 & 1 you can also have 1 &-8.

factors of 9:

9 & 1

-9 & -1

3 & 3

-3 & -3

So now we just need to find numbers where

a & b are factors of 9 and c & d are factors of -8 and a*c+b*d=-6,

if that is the case then (ax+c)*(bx+d)=9x^2-6x-8

guess: 3 & 3 and -4 & 2

3*(-4) + 3*2=-12 +6 = -6

so one factoring is (3x-4)*(3x+2)

This means that one of the possible dimensions of the blanket is (3x-4) by (3x+2)

guess: -3 & -3 and 4 & -2

(-3)*4+(-3)*(-2)= -12+6 = -6

so another factoring is (-3x+4)*(-3x-2)

So you could also have a blanket with dimensions (-3x+4) by (-3x-2) but this might not make sense to do because, if you input positive numbers for x you will get negative dimensions which in the real world don't exist for a knitted blanket.

p.s sorry for the late response.

3 0

3 years ago

The right end of a relaxed standard spring is at the origin; the left end is clamped at some point on the negative x-axis. Holdi

ella [17]

The work required to stretch the spring is 350J.

<h3>Hooke's Law</h3>

This law can be written by the formula: F=kx, where:

F= elastic force (N)

k= spring constant (N/m)

x= linear displacement (m)

<h3>Spring Work</h3>

For finding the spring work in J, you should apply the formula $W=\frac{k*(\Delta x)^2}{2}$ , where:

W= work (J)

k= spring constant (N/m)

x= difference between the linear displacements (m)

The question gives:

x=5 cm=0.05m requires a force of 1.4N

x=8 cm =0.08m

Step 1 - First, you should find the spring constant from Hooke's law, for x=5 cm and F=1.4N.

$F=kx\\ 1.4=k*0.05\\ \\ k=\frac{1.4}{0.05} =28\frac{N}{m}$

Step 2 - Now you can apply the formula for spring work.

$W=\frac{k*(\Delta x)^2}{2}\\ \\ W=\frac{28*(8-3)^2}{2} \\ \\ W=\frac{28*(5)^2}{2}\\ \\ W=\frac{28*25}{2}\\ \\ W=\frac{700}{2}=350J$

Read more about the spring work here:

brainly.com/question/3317535

5 0

3 years ago