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Aleks04 [339]
3 years ago
15

Scale drawing to find an area of 6.5 inches and 5 inches

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0
2, he answer is 2 do not question my answer
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A researcher measures daily driving distance from college and weekly cost of gas for a group of commuting college students. What
juin [17]

Answer:

There is a positive correlation between these two variables.

Step-by-step explanation:

Positive correlation is an association amid two variables in which both variables change in the same direction.  

A positive correlation occurs when one variable declines as the other variable declines, or one variable escalates while the other escalates.

As the distance covered by the vehicle increases the amount of gas consumed also increases. Thus, the weekly cost of gas will also increase.

Thus, there is a positive correlation between these two variables.

6 0
3 years ago
Jasmine wants to buy a new backpack that cost $50 if the tax rate is 6.5% how much will she pay when she buys the backpack
melomori [17]
50 + (50 * 0.065) = the answer, sorry I don't have my calculator on me.



3 0
3 years ago
Read 2 more answers
Look at pic pleaseujjjjj
densk [106]
It’s gonna be less than 50 percent bc the majority gets warm
7 0
3 years ago
Plz explain and prove the triangles congruence.
amm1812

Answer:

ΔNAS≅ΔSEN by SSA axiom of congruency.

Step-by-step explanation:

Consider ΔNAS and ΔSEN,

NS=SN(Common ie . Both are the same side)

SA=NE( Given in the question that SA≅ NE)

∠SNA=∠NSE( Due to corresponding angle property where SE ║ NA)

Therefore, ΔNAS ≅ΔSEN by SSA axiom of congruency.

∴ NA≅SA by congruent parts of congruent Δ. Hence, proved.

8 0
3 years ago
The value of a car depreciates by 40% each year. At the end of 2007 the value of the car was £3600 Work out the value of the car
natima [27]

Answer: $6,000

Step-by-step explanation: If set up correctly, the value of the car at the end of 2006 times 0.6 (because the car is losing 0.4 of its value, so it keeps 0.6 of its value) should get you the value of the car at the end of 2007.

The equation should look like this:

(value of the car at the end of 2006) x 0.6 = (value of the car at the end of 2007)

Then you substitute: (value at the end of 2006) x 0.6 = 3600

Then divide: (value at the end of 2006) = 0.6 ÷ 3600

Then substitute again: (value at the end of 2006) = 6,000

Hope this helped you! Feel free to ask me any questions!

3 0
3 years ago
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