Answer:
The class 35 - 40 has maximum frequency. So, it is the modal class.
From the given data,
MODE
- Most precisely, mode is that value of the variable at which the concentration of the data is maximum.
MODAL CLASS
- In a frequency distribution the class having maximum frequency is called the modal class.
Where,
Answer: 195
Step-by-step explanation:
Cost per student = $4
Total number who attended = n
The cost of the total of student who attended will be cost per student multiplied by the total number of students, that is
Total cos = 4n
Since, they are to pay $140 , for publicity, then the total cost becomes
T = 4n - 140
From the last statement
4n - 140 ≥ 640
4n ≥ 640 + 140
4n ≥780
n ≥ 780/4
n ≥ 195
That means at least 195 students must attend if the science club is to earn at least $ 640
(A) Product of 
and 
is:
(B) Yes.
Product of and = Product of and because multiplication is commutative.
Commutative Property of multiplication says that a.b = b.a.
Thus, multiplication is same irrespective of the order of two numbers.
Answer:
d = 1.46 m
Step-by-step explanation:
We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:
From the question given above,
F is inversely proportional to square of d. This can be written as:
F ∝ 1/d²
F = K/d²
Cross multiply
K = Fd²
But:
Force (F) = 0.006 N
Distance (d) = 4 m
Constant (K) =?
K = Fd²
K = 0.006 × 4²
K = 0.006 × 16
K = 0.096 Nm²
Therefore, the relationship between the force (F) and the distance (d) is:
F = K/d²
F = 0.096 / d²
Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:
Force (F) = 0.045 N
Constant (K) = 0.096 Nm²
Distance (d) =?
F = K/d²
0.045 = 0.096 / d²
Cross multiply
0.045 × d² = 0.096
Divide both side by 0.045
d² = 0.096 / 0.045
Take the square root of both side.
d = √(0.096 / 0.045)
d = 1.46 m.
Answer:
2.7
3
6
Step-by-step explanation:
2.7×3 = 8.1
3x3=9
6×3= 18
18-8.1= 9.9 < 10
18-9= 9 < 10
18-18=0 < 10
