$\bf \cfrac{(6x^3y^{-4})^{-2}}{(3x^2y^5)^{-3}}\implies \stackrel{\textit{using positive exponents}}{\cfrac{(3x^2y^5)^3}{(6x^3y^{-4})^2}}\implies \stackrel{\textit{distributing the exponent}}{\cfrac{(3^3x^{2\cdot 3}y^{5\cdot 3})}{(6^2x^{3\cdot 2}y^{-4\cdot 2})}} \\\\\\ \cfrac{27x^6y^{15}}{36x^6y^{-8}}\implies \cfrac{27}{36}\cdot \cfrac{x^6y^{15}}{x^6y^{-8}}\implies \cfrac{3}{4}\cdot x^6x^{-6}y^{15}y^8\implies \cfrac{3}{4}\cdot x^{6-6}y^{15+8} \\\\\\ \cfrac{3}{4}\cdot 1y^{23}\implies \cfrac{3y^{23}}{4}$

6 0

2 years ago

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Helllllppppppppppppppp thank you

Alisiya [41]

√4=2, and √45=√(9*5)=√9 *√5=3√5
so you have 2/(3√5)
Multiply both top and bottom by √5 to eliminate the √ in the denominator:
(2√5)/15 is the final answer.

5 0

2 years ago

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What are the coordinates of Point A after the

Flura [38]

Answer:

A' (-3,7)

B' (0,10)

C' (12,10)

D' (-2,-4)

Step-by-step explanation:

A' (-6+3 , 3+4) = (-3,7)

B' (-3+3 , 6+4) = (0,10)

C' (9+3 , 6+4) = (12,10)

D' (-5+3 , -8+4) = (-2,-4)

5 0

2 years ago

Which is the value of the expression when x=-2 and y =-3

a_sh-v [17]

Answer:

-720

Step-by-step explanation:

10x^3y^2 If x = -2 and y = -3

10 * (-2^3) * (-3^2)

10 * (-8) * (9) = -720

6 0

2 years ago

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