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nirvana33 [79]
3 years ago
15

What are my questions

Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0
Idk what are your questions?
Ira Lisetskai [31]3 years ago
7 0
I don’t know what the question is.......
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Some day help me with this 2 question?
gregori [183]

Answer:

As x approaches 0, f(x)=2

Step-by-step explanation:

First plug in f(x) and f(0) into the limit.

\lim_{x \to 0\0} 2x^2+1-(2(0^2)+1)/x^2\\\\, simplify things a bit

\lim_{x \to \ 0} 2x^2/x^2,   divide by x^2

\lim_{x \to \ 0} 2/1=2, as x approaches 0, f(x)=2

6 0
3 years ago
Write the next three terms in each sequence. Make sure your
makvit [3.9K]

Answer:

29,30,31

this is basically like counting just add 1

8 0
3 years ago
Alex was biking along a 48 mile trail. First half of the time he was biking twice as fast as the second half of the time. If he
nydimaria [60]

Answer:

The speed in the first part is 16 mph.

Step-by-step explanation:

The total distance is 48 miles. The total time is 4 hours.

In the second part of the trip, he was traveling at speed s for distance d for 2 hours.

In the first part of the trip he was traveling at twice the speed, or 2s, for distance 48 - d, for 2 hours.

speed = distance/time

distance = speed * time

First part of trip:

48 - d = 2s * 2

d + 4s = 48   Equation 1

Second part of the trip:

d = s * 2

d = 2s    Equation 2

Equations 1 and 2 form a system of equations in two unknowns, d and s.

d + 4s = 48

d = 2s

Substitute 2s for d in equation 1.

2s + 4s = 48

6s = 48

s = 8

The speed in the second part is 8 mph.

The speed in the first part is 2s = 2(8) = 16.

The speed in the first part is 16 mph.

Check:

d = 2s = 2(8) = 16

48 - d = 48 - 16 = 32

The second part is 16 miles. The first part is 32 miles.

16 miles at 8 mph takes 2 hours.

32 miles at 16 mph takes 2 hours.

2 hours + 2 hours = 4 hours.

Our answer is correct.

Answer: The speed in the first part is 16 mph.

7 0
3 years ago
Identify the expression as a numerical expression or variable expression I•8
user100 [1]

A is the answer because the number 8 is a constant. and the multiplication sign is the operator.

6 0
3 years ago
Determine the zeroes of the polynomial
Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)}  \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)}  -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\

\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}

8 0
3 years ago
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