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Jlenok [28]
2 years ago
5

I don't know how to do this. Any help?

Mathematics
1 answer:
Brut [27]2 years ago
7 0

Answer:

cos 37=x/b (second one)

sin 37= a/b (third one)

tan 37=a/x (sixth one)

Step-by-step explanation:

Cos is defined by the adjacent side over the hypotenuse. Cos 37 would be x/b. Clearly, that is option 2. Sin is defined by opposite over hypotenuse. Sin 37 would be a/b. That is the 3rd option. Tan is defined by opposite over adjacent. Tan 37 would be a/x or the 6th option.

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Answer:

A and B

Step-by-step explanation:

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2 years ago
18-3+5-12÷4. I am needing help on how to work this problem
AleksandrR [38]

Answer

Step-by-step explanation:

12 divided by 4=3

18-3+5-3

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3 years ago
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What is the equation of this line?<br> o y = -1/4x<br> o y = – 4x<br> o y = 1/4x<br> O y = 4x
Kitty [74]

Answer:

<h2>Its C. y = 1/4x</h2>

Step-by-step explanation:

Look at the line. See where it attaches at one point and look where it attaches to another, for example, in this expression, it attaches to (0,0) and (4,-1). Then do rise over run, or y over x. This means to do this- y2 - y1 divided by x2 - x1. First, do -1 - 0. Its a double negative, so it becomes positive, thus making it 1 - 0, which is still 1. Then do 4 - 0, which is still 4. Divide 1 by 4, turn it to a fraction, and boom, you've got 1/4x.

Hope this helps!!!!![?][?][?]

8 0
2 years ago
The area of a rectangle is 2x*2-13x+12 and another area is 6x^2-13x+21, what is the combined area of both rectangles?
saul85 [17]

Answer:

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Step-by-step explanation:

Add the expressions.

2x^2 - 13x + 12 + 6x^2 - 13x + 21 =

= 2x^2 + 6x^2 - 13x - 13x + 12 + 21

= 8x^2 - 26x + 33

8 0
2 years ago
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