We are given with a velocity-distance-time kinematic problem given the different times of two runners and is asked for the difference in distances the runner has ran in the track. we use the formula v= d/t where d is the distance of running, t is time and v is the velocity of the runner.
First runner,
v = d/t = 1000 m / (120+28.13s ) = 6.750826976 m/s
Second runner
Using the same velocity we determine d2.
v = d2/t2 = d2 / (120+28.48s) = 6.750826976 m/s ; d2 = 1002.362789
distance of running track is the difference of the two distance achieved by the runners, delta d= d2 - d = 2.362789 m
By the work-energy theorem, the total work done on the car is equal to the change in its kinetic energy:
<em>W</em> = ∆<em>K</em>
<em>W</em> = 1/2 (0.34 kg) (22.9 m/s)² - 1/2 (0.34 kg) (6.5 m/s)²
<em>W</em> ≈ 82 J
Water freezes at zero degrees Celsius (32 degrees Fahrenheit). The solid ice particles absorb heat energy from the warmer air, giving the particles energy and enabling them to move away from one another. ... This is what happens when the ice cube (a solid) turns into water (a liquid)
Answer:
Leading your people into the right direction, and always knowing what is best for you and your people.
Explanation:
