initial acceleration of rocket is given as
a = 12 m/s^2
h = 26 m
now we can use kinematics to find its speed
now after this it will be under free fall
so now again using kinematics
at maximum height
total height from the ground = 31.8 + 26 = 57.8 m
Part b)
now after reaching highest height it will fall to ground
So in order to find the speed we can use kinematics again
Part c)
first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s
now we have
after this it will reach to highest point and final speed becomes zero
now from this it will fall back to ground and reach to final speed 33.67 m/s
now we have
so total time is given as
<em>t = 3.44 + 2.55 + 2.1 = 8.1 s</em>
Answer:
voltage ÷ resistance; therefore
20 ÷ 4 = 5 amps
<h2>
Answer: B) It would be best to use a concave mirror, with the object to be ignited positioned halfway between the mirror and its center of curvature. </h2>
Explanation:
To start a fire it is more optimal to use a concave mirror than a plane mirror. This is because the concave mirror allows concentrating sunlight at a point (the focal point) on an object that acts as fuel and ignite the fire there.
For this it is necessary the object to be positioned between the center of curvature of the mirror and the mirror (its focus). Thus the rays of the Sun, when converging on the focus, will heat the object and make it burn.
Hence, the correct option is B.
Answer: 3 seconds
Explanation:
Initial velocity(u) of projectile A in vertical direction = 0m/s
acceleration due to gravity a=g=9.81m/s^2
Time taken(t) of projectile A = 3s
Initial velocity of projectile B = 0m/s(vertical direction)
We can get height of cliff using parameters of projectile A since it's the same location.
Height(S) = u×t + 0.5×a×t^2
u =0
S= 0.5×9.81×3^2 = 44.145m
Time taken for projectile B to reach the ground:
S = u×t + 0.5×a×t^2
u =0, S=44.145m, a=9.81m/s^2
44.145 = 0.5×9.81×t^2
44.145 = 4.905×t^2
44.145 ÷ 4.905 = t^2
9 = t^2
t = sqrt(9)
t = 3seconds
Answer:
602.27 kg
Explanation:
The computation of the largest mass of cargo the balloon can lift is shown below:-
Volume of helium inside the ballon= (4 ÷ 3) × π × r^3
= (4 ÷ 3) × 3.14 × 6.953
= 1406.19 m3
Mass the balloon can carry = volume × (density of air-density of helium)
= 1406.19 × (1.29-0.179)
= 1562.27 kg
Mass of cargo it can carry = Mass it can carry - Mass of structure
= 1562.27 - 960
= 602.27 kg
