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a_sh-v [17]
3 years ago
10

Two crates, of mass m1 = 71 kg and m2 = 130 kg , are in contact and at rest on a horizontal surface. Force F = 610 N is exerted

on the 71-kg crate. The coefficient of kinetic friction is 0.18.
1. Determine the acceleration of the system.
2. Determine the magnitude of the force that each crate exerts on the other.
Physics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer: Respective answers are 1.27 m/s^2 and 90.17 N

Explanation:

Explanation requires basic knowledge of forces in physics. The solutions are attached in this response. To summarize:

- Newton's Second Law -> F = ma

- Force of friction = Fn (normal force) x µk (coefficient of kinetic friction)

- Because the surface is leveled, Fn = Fg, Fg = mg

- The crates exert the same amount of force on each other because of the rule of action // reaction (Newton's Third Law)

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For the front glass of the car to get wet, V_c \geq 10 \ m/s.

The given parameters:

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V_{C/R} = V_C- V_R

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A block rests on a frictionless table on Earth. After a 40-N horizontal force is applied to the block, it accelerates at 9.2 m/s
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4.6 \frac{m}{s^2}

Explanation:

Since the table is frictionless, there is no force of dynamic  friction between table an block when the horizontal force is applied to it on Earth. Exactly the same is true when the table is taken to the Moon. Therefore, the Net Force acting on the object in both cases when the object accelerates, is the external horizontal force.

Notice that on Earth and on the Moon, the weight of the object (vertical and pointing up) is compensated by the normal force of the table on the object (pointing up and of the same magnitude as the weight) that precludes movement in the vertical direction. So in both cases, its acceleration will only be due to the horizontal force.

We use the equation for Net Force to find the mass of the object:

F=m*a\\40 N =m * 9.2 \frac{m}{s^2}\\\frac{40}{9.2} kg=m\\m=\frac{40}{9.2} kg

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f=m*a\\20N=\frac{40}{9.2} kg*a\\20*9.2=40*a\\\frac{20*9.2}{40} =a\\a=\frac{9.2}{2} \frac{m}{s^2} \\ a=4.6 \frac{m}{s^2}

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I = 3.12 Kg.m²

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