1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nalin [4]
3 years ago
14

Bob Beamon's 1968 Olympic long jump set a world record which remains unbroken to this day. This amazing jump resulted from an in

itial velocity of 9.5 m/s at an angle of 40 degrees from the horizontal.
1. Calculate the initial horizontal velocity (V_ix) to two significant figures:

2. Calculate the initial vertical velocity (V_iy) to two significant figures:

3. Calculate the time needed to reach the highest point of the jump (t_1/2) to two significant figures:

4. Calculate the total time (t_TOT) needed to complete the jump to two significant figures:

5. Calculate the maximum height (h) reached during the jump to two significant figures:

6. Calculate the range (total horizontal distance) of his jump to two significant figures:

Please answer today! Thanks!
Physics
2 answers:
drek231 [11]3 years ago
8 0

Answer:

1.) 7.3 m/s 2.) 6.1 m/s

Explanation:

To calculate the initial horizontal velocity with just degrees and velocity alone is pretty simple. The formula is     Velocity*cos(degrees)

eg 9.5*cos(40)

2.  To calculate the initial vertical velocity with just degrees and velocity alone is pretty simple. The formula Velocity*sin(degrees)

eg 9.5*sin(40)

notsponge [240]3 years ago
6 0
9-+6 i think !!!! Or 2-+9x1
You might be interested in
I am so confused by this! Someone, please help me! This isn't a test or homework question, just me being really confused!
Molodets [167]
Relativistic mean its so fast its a fraction of the sped of light.
3 0
4 years ago
Bats are extremely adept at catching insects in midair. If a 81.5-g bat flying in one direction at 7.21 m/s catches a 8.11-g ins
aivan3 [116]
You can look that up on google
7 0
3 years ago
How can a surface be smooth/polished for some waves and not for others? (This is an important question, refer to the homework on
77julia77 [94]

Answer:

Depending upon the size of the irregularities on the surface and the wavelength of the surface a surface can be smooth for the waves of smaller wavelengths than the size of the irregularities.

Explanation:

Depending upon the size of the irregularities on the surface and the wavelength of the surface a surface can be smooth for some of the waves but not for the others.

  • More specifically, when a surface has irregularities of the size greater than or equal to the wavelength of a wave then the surface is rough for that particular wave and causes irregular reflection in the incident light.

Contrarily, when the surface has the irregularities less than the size of the wavelength then it reflects most of the light in a uniform manner.

5 0
3 years ago
An automobile accelerates from rest at 2.0 m/s2 for 20 s. The speed is then held constant for 20 s, after which there is an ac-
MaRussiya [10]

Answer:

1446.7m

Explanation:

You need to look at this in 3 separate stages, and then sum thedistance from each stage:

Stage 1)

a=2

t=20

V_0=0

s=V_0t+\frac{1}{2}g t^2

x=400m

We also need to find the final velocity v=a*t=20*2=40m/s

Stage 2)

a=0

v=40

t=20

x=vt

x=800m

Stage 3)

a=-3

v_0\\=40

v=0

v^=v_0^2 + 2 a x\\0=40^2+2*(-3)x\\x=266.7m

So the total distance is x=400+800+266.7=1466.7m

5 0
3 years ago
SHOW WORK
Helga [31]

Answer:

Follows are the solution to the given question:

Explanation:

For point a:

T= 2\pi \sqrt{\frac{m}{k}}\\\\k = \frac{4 \pi^2 m}{T^2}\\\\= \frac{4 \times (3.14)^2 \times 3}{2^2}\\\\=29.578 \ \frac{N}{m}\\\\

For Point b:

E=\frac{1}{2} m a^2 w^2\\\\

   =\frac{1}{2} \times m \times a^2 \times \frac{4\pi^2}{T^2}\\\\=\frac{1}{2} \times 3 \times (0.15)^2 \times \frac{4\times 3.14^2}{2^2}\\\\=0.332 \ J

For Point C:

V_{max}= a w

        = (0.15) \times \frac{2\pi}{T}\\\\= (0.15) \times \frac{2\times 3.14}{2}\\\\=0.471 \frac{m}{s}

For point D:

X= a \sin (wt+ \phi)\\\\0.91=0.15 \sin(\frac{2\pi}{T} \times t+\phi)\\\\0.91=0.15 \sin(\frac{2\times 3.14}{2} \times 0.5+\phi)\\\\0.60 = \sin(3.14 \times 0.5+\phi)\\\\0.60 = \sin(1.57+\phi)\\\\1.57 +\phi =\sin^{-1} 60^{\circ}\\\\1.57 +\phi = 36.86^{\circ}\\\\=35.29^{\circ}\\\\So, X=15 \sin(3.14t+35.29^{\circ}) \ cm

5 0
3 years ago
Other questions:
  • A device called an insolation meter is used to measure the intensity of sunlight. It has an area of 100 cm2 and registers 6.50 W
    15·1 answer
  • Why is the question correct
    5·1 answer
  • A fixed mass of an ideal gas is heated from 50 to 80℃ at a constant pressure of (a) 1 atm and (b) 3 atm. for which case do you t
    6·1 answer
  • A 60-watt light bulb has a voltage of 120 bolts applied across it and a current of 0.5 amperes flows through the bulb. What is t
    9·1 answer
  • If the change in velocity increases, what happens to the acceleration during the same time period?
    14·2 answers
  • A thin cylindrical pressure vessel of 250 mm diameter and 5 mm thickness is rigidly attached at one end. Determine maximum shear
    9·1 answer
  • Why dont we put (-ve) sign when calculating charge in electrostatics ?​
    10·1 answer
  • the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ
    8·1 answer
  • a 250kg box is being push with a force of 100N to the left and 225n to the right determine the acceleration
    8·1 answer
  • To reduce friction on an aircraft, the surfaces (skin) are ? and the body is ?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!