This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.
Answer:
The new speed of the aircraft with respect to the ground is 1414.3 mph.
Explanation:
Given that,
Angle = 37°
Velocity of jet airliner = 693 mph
Velocity of wind = 798 mph
We know that,
The new velocity of the aircraft with respect to the ground
We need to calculate the new speed of the aircraft with respect to the ground
Using formula for velocity
Put the value into the formula
Hence, The new speed of the aircraft with respect to the ground is 1414.3 mph.
Answer: Fr = 26.53 N
Explanation: The constant force exerted on the block by the surface is the frictional force.
This frictional force is as a result of interaction between the body and the surface.
According to newton's second law of motion,
F - Fr = ma
F=applied force
Fr = magnitude of frictional force
m = mass of object = 12kg
a = acceleration of object = 3.2m/s²
The applied force (F= 75 N) is inclined at an angle of 30° to the horizontal thus making it have 2 components of forces given below
Fx = 75 * cos 30 = 64.95 N (horizontal component)
Fy = 75 * sin 30 = 37.5 N ( vertical motion)
The body moves across the surface, hence the horizontal component of force is responsible for motion.
F = 64.95 N
By substituting the parameters, we have that
64.96 - Fr = 12 * 3.2
64.96 - Fr = 38.4
Fr = 64.96 - 38.4
Fr = 26.53 N
<span>B. Reviewing the competency of health care workers</span> is considered part of health care operations
