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Ket [755]
2 years ago
6

What are the advantages of using digital signals over analog signals?

Physics
1 answer:
Snezhnost [94]2 years ago
4 0

Digital signals are advantageous over analog signals because they are easily reproducible and convey information with little interference.

<h3>What are analog and digital signal?</h3>

Analogs signals are signal which are continuous whereas digital signals are signal which are not continuous but are separated by time.

Use of digital signals are most common because they have certain advantages over analog signals.

Some advantages of digital signals over analog signals include:

  • Digital signals can convey information with less noise and interference.
  • Digital circuits can be easily reproduced

Therefore, Digital signals are advantageous over analog signals because they are easily reproducible and convey information with little interference.

Learn more about digital and analog signals at: brainly.com/question/14729899

#SPJ1

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50 POINTS HELP ME PLEASE!!!!!!!!!!!!
Mariana [72]

Answer:

W and X

Explanation:

When escaping a rip current, one should always walk to the side until you escape from the rip current. If you walk towards the shore, you have the ability to keep getting dragged toward the current, such as with X and Y.

4 0
3 years ago
Read 2 more answers
The difference in electronegativity values between H and O is 1.4. What type of bond will these elements form?
Gnoma [55]
Who what where when why how ?
6 0
3 years ago
1. The current in a wire is 0.72A. Calculate the charge that passes through the wire in; a. 4 s b. 60 s c. 180 s d. 7 s e. 0.5 s
Vlad [161]
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t

Case I
---------
When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C

Case II
----------
When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C

Case III
-----------
When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C

Case IV
-----------
When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C

Case V
----------
When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
6 0
3 years ago
What is the approximate value of the gravitational force between a 73 kg astronaut and a 7.1×104 kg spacecraft when they're 89 m
Luden [163]

Answer:

F = 4.3671 * 10^{-8}\ Newtons

Explanation:

The gravitational force between two corpses is given by the following equation:

F = GMm/d^2

Where F is the force, G is the gravitational constant

(G = 6.67408*10^{-11}\ m^3kg^{-1}s^{-2}), M and m are the masses of the corpses and d is the distance between them.

So we have that:

F = 6.67408*10^{-11} * 7.1*10^4 * 73/89^2

F = 4.3671 * 10^{-8}\ Newtons

5 0
3 years ago
Letícia leaves the grocery store and walks 150.0 m to the parking lot. Then, she turns 90° to the right and walks an additional
Alexxx [7]

Answer:

165.529454

Explanation:

According to the Pythagorean Theorem for calculating the lengths of a right angle triangle's sides, a^2 + b+2 = c^2, where c is the longest side (and the side opposing the right angle). So in your case it would be 150*150 + 70*70 = 27400. And √ 27400 is your answer.

7 0
3 years ago
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