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2 years ago

Ok ok ik ik this is not the answer but I think you need to hear this

Physics

1 answer:

leonid [27]2 years ago

4 0

Answer

oh thanksssss i hope u have a great day

Explanation:

ur a really awesome person and i thank u for that

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Select the correct answer.

anyanavicka [17]

<h2>MULTIPLE CHOICES</h2>

$\large\mathcal{QUESTION:}$

What is the basic unit of all matter?

$\large\mathcal{CHOICES:}$

OA neutron
OB. atom
OC. electron
OD. proton
OE. nucleus

$\large\mathcal{ANSWER:}$

B. Atom

_____

<u>Atom</u> is the smallest, <u>indivisible unit of a chemical</u> <u>element and the fundamental unit of matter</u>. It consists of a nucleus (neutrons + protons) surrounded by an electron cloud. The <u>atom</u> is the smallest unit of matter that cannot be divided chemically and is a building block with its own set of properties.

<h3>#ProvideUniqueAnswers</h3>

6 0

2 years ago

Which statement is a description of boyle's law?The temperature and volume of a gas are directly proportional when pressure is c

torisob [31]

P and V are inversely proportional when temperature is constanst.
answer is the last option.

6 0

3 years ago

Read 2 more answers

A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e

balandron [24]

Answer:

0.00001 J

Explanation:

$k.e = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2} \\ = 0.00001j$

3 0

3 years ago

(1) Assume that the lights in your kitchen use 300 watts. How much energy (in kWh) does it use and how much does it cost to leav

lbvjy [14]

Answer:

the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

Explanation:

Given that;

P = 300 watts = 300/1000 = 0.3

t = 24hrs a day

In a calendar year, we have 365 days

so;

E = 0.3 × 365 × 24

E = 2628 KWh

given that; 1 KWh = 12 cent

then 2628 KWh is x

x = 2628 × 12

x = 31,536 cents or 315.36 dollars

Therefore, the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

7 0

3 years ago

A 320-kg satellite experiences a gravitational force of 800 N. What is the radius of the satellite’s orbit? What is its altitude

Westkost [7]

Answer:

Radius of orbit = 3.992 × $10^{7}$ m

Altitude of Satellite =33541.9× m

Explanation:

Formula for gravitational force for a satellite of mass m moving in an orbit of radius r around a planet of mass M is given by;

$F= G\frac{m M}{r^{2} }$

Where G = Gravitational constant = 6.67408 × 10-11 $\frac{m^{3} }{Kg sec^{2} }$

We are given

F= 800 N

m = 320 Kg

M = 5.972 × $10^{24}$ Kg

G = 6.67408 × 10-11 $\frac{m^{3} }{Kg sec^{2} }$

We have to find radius r =?

putting values in formula;

==> 800 =6.67408 × $10^{-11}$ × 320 × 5.972 × $10^{24}$ / $r^{2}$

==> 800= 39.8576 × $10^{13}$ × 320 / $r^{2}$

==> 800 = 12754.43 × $10^{13}$ / $r^{2}$

==> $r^{2}$ = 12754.43 × $10^{13}$ /800

==> $r^{2}$ =15.94 × $10^{13}$

==> r = 3.992 × $10^{7}$ m

==> r = 39920× $10^{3}$ m

This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.

Radius of earth =6378.1 km = 6378.1 × $10^{3}$ m

Altitude = 39920× $10^{3}$ - 6378.1 ×

3 0

3 years ago