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2 years ago

Guys No one's answering my question so sad! Once again I'm asking the same question –Here

Physics

1 answer:

nexus9112 [7]2 years ago

8 0

For the front glass of the car to get wet, $V_c \geq 10 \ m/s$ .

The given parameters:

Speed of the car, = Vc
Speed of the rain, = 10 m/s

The relative velocity of the car with respect to the falling rain is calculated as;

$V_{C/R} = V_C- V_R$

If the speed of the car equals the speed of the rain, the rain will fall behind the car.
If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
If the speed of the car is greater than speed of the rain, the rain will fall on the car.

Thus, for the front glass of the car to get wet, $V_c \geq 10 \ m/s$ .

Learn more about relative velocity here: brainly.com/question/17228388

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Can someone help me answer please

Andru [333]

Answer:

4=Conduction by convection by radiation.

Explanation:

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5 0

3 years ago

Light in the air is incident at an angle to the surface of (12.0 A) degrees on a piece of glass with an index of refraction of (

Orlov [11]

The question is incomplete. You dis not provide values for A and B. Here is the complete question

Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.

A = 12

B = 18

Answer:

18.5⁰

Explanation:

Angle of incidence i = 12.0 + A

A = 12

= 12.0 + 12

= 14

Refractive index u = 1.10 + B/100

= 1.10 + 18/100

= 1.10 + 0.18

= 1.28

We then find the angle of refraction index u

u = sine i / sin r

u = sine24/sinr

1.28 = sine 24 / sine r

1.28Sine r = sin24

1.28 sine r = 0.4067

Sine r = 0.4067/1.28

r = sine^-1(0.317)

r = 18.481

= 18.5⁰

4 0

2 years ago

An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed, w

Dovator [93]

The elephant and the mouse having zero weight in a gravity free space will not bump into you at the same effect.

Explanation: 

When both are in a gravity free space, the weights are zero, as we know that the $\text {weight of the body}=\text {mass of the body} \times \text {acceleration due to gravity}$

$\text {here, the weight of elephant}=\text {mass of elephant } \times \text {zero gravti} y=zero$

$\text {similarly,weight of mouse}=\text {mass of mouse } \times \text {zero gravity}=zero$

But when they will acquire the speed of same magnitude, say v, their different masses will acquire different momentum, which will make the difference in effect while bumping.

$\text { momentum of elephant }=\text { mass of elephant } \times v$ $\text { momentum of mouse = mass of mouse } \times v$

And as we know $\text { mass of elephant }>\text { mass of mouse }$ Therefore, effect of impact by elephant will be more than that of mouse . An elephant breaking into you will take you back faster than a mouse in space hits you.

8 0

3 years ago

I need some help pls

Lina20 [59]

Answer:

And the bigger intensity

Explanation:

4 0

3 years ago

Find acceleration given the following:

Lorico [155]

Answer:

Explanation:df=378

Di=0

Vi=0

T=6s

Formula

Df=Di+Vit+1/2(at)2

378=0+0+6+1/2×a×t2

378=6+1/2×a×36

378=6+18a

18a=378+6=384

a=385/18=21.33(cm/s)/s

5 0

3 years ago