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Fantom [35]
3 years ago
15

Can someone plz help me!??!

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0
To solve for x, you simplify both sides of the equation and then isolate the variable.

<em>10x + 12 = $72.00</em>
<em>x = 6</em>

Six people attended the concert.
<em>Check the answer:
(10 • 6) + 12 = 72.00
60 + 12 = 72.00
_____________________________________________________________
<u>Answer: x = 6</u></em>
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Solve the system of equations<br> y=x^2-3x+4<br> x+y=4<br> show all work please!
Debora [2.8K]

Answer:

(0,4)

(2,2)

Step-by-step explanation:

y=x^2-3x+4

x+y=4

the second one can be rewritten as y=4-x

so the system becomes

y=x^2-3x+4

y=4-x

therefore 4-x = x^2-3x+4

that is x^2-2x=0

we can write it as x(x-2)=0 a product is = 0 when one of its factors = 0

so the solutions for x are: x=0 and x-2= 0 that means x=2

to get y you simply use 0 and 2 as value of x for any of the two equations

and you get y=4 and y=2 respectively

6 0
3 years ago
Stephanie is trying to figure out the sample size of an experiment. She knows the population SD is 41.5 and the SD of the sample
Bond [772]
B I smskksss snsjsjsjsjs wjqjwjqjwjjw xixxiidididid a hahaha dixixidjjdjjs w
6 0
3 years ago
Can someone please help, ty!!<br> (Will mark brainliest)
PolarNik [594]

Answer:

Yellow is correct.

You can add the valued and divide by how many values there are to find the mean

The score of 20 is an outlier and brings the mean score down by almost 10%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
AD = 6x - 4 and AC = 4x - 3
salantis [7]

Answer:

CD= 2x-1

Step-by-step explanation:

AD = 6x-4

AC = 4x - 3

CD= AD- AC

CD=  6x-4 - (4x - 3)

CD= 6x - 4 - 4x +3

CD= 2x -1

Therefore, the value of CD= 2x-1

3 0
2 years ago
What is the length of segment CD question mark
blagie [28]

Answer:

CD = two square root of 10 end square root

Step-by-step explanation:

To find the length of a segment, use the distance formula. Substitute the order pairs for the endpoints of the segment. CD has the end points (-7, -4) and (-1, -2).

d = \sqrt{(y_2-y_1)^2 + (x_2-x_1)^2} \\\\d = \sqrt{(-4--2)^2 + (-7--1)^2} \\\\d = \sqrt{-2^2 + -6^2}\\\\d = \sqrt{4 + 36}\\\\d=\sqrt {40} = 2\sqrt{10}

8 0
3 years ago
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