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makvit [3.9K]
3 years ago
9

For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo

rce on their feet compared to when they are running in a straight line?
Physics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

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F = G m1*m2 / r^2 => [G] = [F]*[r]^2 /([m1]*[m2]) = N * m^2 / kg^2

That is one answer.

Also, you can use the fact that N = kg*m/s^2

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5 0
3 years ago
You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
Fed [463]

Answer:

9.81 × 10⁻¹⁰ C

Explanation:

Given:

Distance between the tissue and the tip of the scale, r = 6 cm = 0.06 m

Charge on the ruler, Q = - 12 μC = - 12 × 10⁻⁶ C

Mass of the tissue = 3 g = 0.003 Kg

Now,

The force required to pick the tissue, F = mg

where, g is the acceleration due to gravity

also,

The force between (F) the charges is given as:

F=\frac{kQq}{r^2}

where,

q is the charge on the tissue

k is the Coulomb's constant = 9 × 10⁹ Nm²/C²

thus,

mg=\frac{kQq}{r^2}

on substituting the respective values, we get

0.003\times9.81=\frac{9\times10^9\times(-12\times10^{-6})\times q}{0.06^2}

or

q = 9.81 × 10⁻¹⁰ C

Minimum charge required to pick the tissue paper is 9.81 × 10⁻¹⁰ C

3 0
3 years ago
From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of
alexandr1967 [171]

Answer:

The  value is  h  = 11930 \ m

Explanation:

From the question we are told that

    The  temperature is  T  =  300 \  K

     

Generally the root mean square speed of the  oxygen molecules is mathematically represented as

        v  =  \sqrt{\frac{3 *  R  *  T }{M} }  =  \sqrt{ 2 *  g  *  h }

Here  R is the gas constant with a value  R  =  8.314 \  J\cdot K^{-1} \cdot \  mol^{-1}

    M  is the molar mass of oxygen molecule with value M  =  0.032 \  kg /mol

So  

     \frac{3 *  8.314   *  300 }{0.032}   =  2 *  9.8  *  h

=>    h  = 11930 \ m

   

4 0
3 years ago
Describe how the forces of gravity and friction affect the motion that occurs as you write on this page.
Zinaida [17]

Answer:

Friction is a force that slows down the motion of a moving object. ... Eventually, friction and gravity will work together to stop the motion of the slide. Gravity is a force that pulls two objects toward each other because of their mass. Mass is the measurement of the amount of material (matter) that makes up an object.

6 0
2 years ago
What do we call a substance in<br> which two or more elements are<br> chemically bonded
Goryan [66]

Answer:

A compound

Explanation:

A compound is a substance formed when two or more elements are chemically joined

8 0
3 years ago
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