Answer:
The gravitational acceleration of the planet is, g = 8 m/s²
Explanation:
Given data,
The distance the object falls, s = 144 m
The time taken by the object is, t = 6 s
Using the III equations of motion
S = ut + ½ gt²
∴ g = 2S/t²
Substituting the given values,
g = 2 x 144 /6²
= 8 m/s²
Hence, the gravitational acceleration of the planet is, g = 8 m/s²
Answer:
b) the result we got can be termed approximation because we are neglecting the shear stress acting on the two ends of the cylinder. Here we have considered only the share stress acting on the curved surface area only.
Explanation:
check attachment for solution to A
Answer:
Explanation:
Given
--- Surface Tension
--- Radius
Required
Determine the required force
First, we calculate the circumference (C) of the circular plate
The applied force is then calculated using;
given:
mass = 5000 kg
u (initial velocity) = 0 m/s
v (final velocity) = 70 m/s
time taken to change velocity = 3600 s
acceleration = v - u / t
a = 70 - 0 / 3600
a = 70 / 3600
a = 0.0194 m/s2 (approx)
given: mass = 5000 kg
acceleration = 0.0194 (found in 1st part)
force = mass * acceleration
f = ma
f = 5000*0.0194 = 97 N
therefore the acceleration will be 0.0194 m/s2
and the force involved in acceleration will be 97 N
