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GrogVix [38]
3 years ago
10

1.) if you are sitting still are you accelerating? How do you know?

Physics
1 answer:
castortr0y [4]3 years ago
5 0

yes. gravity is working on you and everything on you.

also earth is rotating


no not in respect ofimmediate surroundings

object could move at constant velocity = no change in either magnitude or direction

change of position "proves" this

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The net external force on the propeller of a 0.75 kg model airplane is 17N forward. What is the
V125BC [204]

Answer:

23 m/s

Explanation:

The net external force on the propeller is 17N

The airplane is 0.75 kg

Therefore the acceleration of the plane can be calculated as follows

= 17/0.75

= 23 m/s

Hence the acceleration of the airplane is 23 m/s

8 0
3 years ago
Please help ! Which of the following objects has the greatest momentum?
Tasya [4]

Answer:

An object with a mass of 0.5 kg and a velocity of 3 m/s

Explanation:

Momentum = mass * velocity

= 0.5 * 3

= 1.5

Highest value among all.

Hope it helps!!

4 0
3 years ago
Does sound travel outside earth's atmosphere in space explain
Yuliya22 [10]
On a large scale, no. Sound travels through space by the compression and relaxation of molecules. When you speak to someone on Earth, each inflection of voice compresses local molecules, and relaxes the molecules around the compressed ones. In space, however, the large lack of molecules means that the compression waves can’t be transmitted from the sound to the listener.
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3 years ago
Which moon phase comes before the phase in this picture?
hodyreva [135]
Waxing gibbous
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8 0
2 years ago
Read 2 more answers
Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s
Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

<u>x-component: </u>

x=V_{o}cos\theta t  (1)

Where:

x is the horizontal distance traveled by the venom

V_{o}=3.10 m/s is the venom's initial speed

\theta=47\° is the angle

t is the time since the venom is spitted until it hits the ground

<u>y-component: </u>

y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}   (2)

Where:

y_{o}=0.44 m  is the initial height of the venom

y=0  is the final height of the venom (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}   (3)

Rewritting (3):

-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0   (4)

This is a quadratic equation (also called equation of the second degree) of the form at^{2}+bt+c=0, which can be solved with the following formula:

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)

Where:

a=-4.9 m/s^{2

b=2.267 m/s

c=0.44 m

Substituting the known values:

t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)} (6)

Solving (6) we find the positive result is:

t=0.609 s (7)

Substituting (7) in (1):

x=(3.10 m/s)cos(47\°)(0.609 s)  (8)

We finally find the horizontal distance traveled by the venom:

x=1.289 m  

7 0
3 years ago
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