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andre [41]
3 years ago
6

Your cousin is currently 10 years old. She will be going to college in 8 years. Your aunt and uncle would like to have $ 105 com

ma 000 in a savings account to fund her education at that time. If the account promises to pay a fixed interest rate of 4.1 % per​ year, how much money do they need to put into the account today to ensure that they will have $ 105 comma 000 in 8 ​years?
Business
1 answer:
telo118 [61]3 years ago
6 0

Answer:

$76,134.84

Explanation:

Data provided in the given question

Future value = $105,000

Fixed interest rate = 4.1%

Number of years = 8

The calculation of present value is given below:-

= Future value ÷ (1 + rate of return)^number of years

= $105,000 ÷ (1 + 4.1%)^8

= $105,000 ÷ 1.379132002

= $76,134.84

Therefore, we simply applied the present value formula.

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Young children are permitted to work in the manufacturing of soccer balls in Pakistan, but this would not be legal in the United
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Answer:

no jodas

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3 years ago
Royal Decking has five products in its inventory. Information about the December 31, 2021 inventory is below:
wariber [46]

Answer:

Royal Decking

A) Per unit value for each of Royal Decking's products, applying LCNRV:

Product   Cost   Sales Price   NRV                          LCNRV

A              $40      $60           $44 ($60 - 12 - 4)      $40

B                80       100           $72 ($100 - 20 - 8)    $72

C                40        80           $60 ($80 - 16 - 4)       $40

D               100      130           $84 ($130 - 26 - 10)   $84

E                 20       30           $22 ($30 - 6 - 2)       $20

B. Total Inventory on the balance sheet is:

$256,000

Explanation:

a) Data and Calculations:

Ending Inventory at December 31, 2021:

Product   Cost   Sales Price   NRV                          LCNRV  Inventory value

A              $40      $60           $44 ($60 - 12 - 4)      $40          $40,000

B                80       100           $72 ($100 - 20 - 8)    $72          $72,000  

C                40        80           $60 ($80 - 16 - 4)       $40          $40,000

D               100      130           $84 ($130 - 26 - 10)   $84           $84,000

E                 20       30           $22 ($30 - 6 - 2)       $20          $20,000

Total inventory value                                           $256       $256,000

= ($256 * 1,000)

Selling costs = 20% of selling price

Shipping costs = 10% of cost

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2 years ago
A _______________ is a supply chain whose members act like a unified system.
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Answer:

e. Vertical marketing system.

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3 years ago
CureAll, a pharmaceutical company, develops a new drug to treat restless legs syndrome. An experiment to test the drug's efficac
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Answer:

double-blind experiment

Explanation:

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The aim of this method is to avoid bias especially from demand characteristics (experimenter expectation) and placebo effect (perception of benefit from an ineffective substance).

Double-blind experiment is used when CureAll develops a new drug to treat restless legs syndrome, and test the drug's efficacy is designed in such a way that neither the experimenter administering the drug or participants knows which drug is administered.

4 0
3 years ago
Suppose 20.0 g pieces of gold and iron, both initially at 100oC, are added to different containers of water, both initially at 2
Sauron [17]

Answer:

  • The final temperature in the container with Gold is 27.49 ⁰C
  • The final temperature in the container with Iron is  33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

Explanation:

Q = mcΔT

Where;

Q is the quantity of heat gained or lost

m is the mass of the metals or water

c is the specific heat capacity

ΔT is the change in temperature, T₂ - T₁

T₂  is the final temperature and T₁ is the initial temperature

Heat lost by metals at 100°C is equal to heat gained by water at 25°C

-Q_{metal} = Q_{water}

-Q_{Au} = Q_{H_2O} \\-Q_{Fe}  = Q_{H_2O}

Specific heat capacity of water = 4.18 J/g°C

Specific heat capacity of gold = 0.129 J/g°C

Specific heat capacity of iron  = 0.45 J/g°C

⇒For Gold

-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)

-2.58T₂ +258 = 75.24T₂  - 1881

77.82T₂  = 2139

T₂  = 2139/77.82

T₂ = 27.49 ⁰C

⇒For Iron

-20*0.450*(T₂ - 100) = 18*4.18 (T₂  - 25)

-9T₂  +900 = 75.24T₂ - 1881

84.24T₂ = 2781

T₂  = 2781/84.24

T₂ = 33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

5 0
3 years ago
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