Question

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

Answer 1

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$  and  $x=\frac{-2+\sqrt{19}}{3}$

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To find the solution of the quadratic equation by using quadratic formula

• Find the values of a, b, and c from the quadratic equation
• Substitute these values in the quadratic formula
• Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ $x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4+\sqrt{16+60}}{-6}$

∴ $x=\frac{4+2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2-\sqrt{19}}{3}$

∵ $x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4-\sqrt{16+60}}{-6}$

∴ $x=\frac{4-2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2+\sqrt{19}}{3}$

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$  and $x=\frac{-2+\sqrt{19}}{3}$

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Answer 2

Answer:

It's A on edg