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mr Goodwill [35]
3 years ago
11

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti

on negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
Mathematics
2 answers:
weqwewe [10]3 years ago
9 0

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

x=\frac{-2-\sqrt{19}}{3}  and  x=\frac{-2+\sqrt{19}}{3}

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}

To find the solution of the quadratic equation by using quadratic formula

  • Find the values of a, b, and c from the quadratic equation
  • Substitute these values in the quadratic formula
  • Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}

∴ x=\frac{4+\sqrt{16+60}}{-6}

∴ x=\frac{4+2\sqrt{19}}{-6}

- Simplify by dividing up and down by -2

∴ x=\frac{-2-\sqrt{19}}{3}

∵ x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}

∴ x=\frac{4-\sqrt{16+60}}{-6}

∴ x=\frac{4-2\sqrt{19}}{-6}

- Simplify by dividing up and down by -2

∴ x=\frac{-2+\sqrt{19}}{3}

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

x=\frac{-2-\sqrt{19}}{3}  and x=\frac{-2+\sqrt{19}}{3}

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

#LearnwithBrainly

patriot [66]3 years ago
8 0

Answer:

It's A on edg

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