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Marrrta [24]
4 years ago
11

A catalyzed reaction will have a ____ activation energy, and this leads to a _____ in the reaction rate.

Chemistry
2 answers:
postnew [5]4 years ago
7 0
The answer is D, a catalyst speeds up the reaction rate so a catalyzed reaction will have higher activation energy thus and increase in rate of reaction.
Dovator [93]4 years ago
3 0

I chose d and got it wrong. The correct answer is b.

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Joel has noticed that his engine is not compressing properly during the compression and ignition step. What problem will this po
denis-greek [22]

The answer is: The engine will run inefficiently APEX....

7 0
3 years ago
The __ is the only vein in the body that carries oxygen-rich blood.
Vesnalui [34]

Answer:

pulmonary vein

Explanation:

The pulmonary vein is the only vein in the body that carries oxygen rich blood.

4 0
3 years ago
When an aqueous solution of silver nitrate is
Andre45 [30]

Answer:

K^{+} and NO_{3}^{-}

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

Ag^{+}(aq) + NO_{3} ^{-}(aq) + K^{+}(aq) + Cl^{-}(aq)  ==> AgCl(s) +

K^{+} and NO_{3} ^{-} do not change, so they are the spectator ions and are removed

The ionic equation is:

Ag^{+}(aq) + Cl^{-}(aq) ==> AgCl(s)

8 0
3 years ago
Find the formula for the hydrate<br>0.737 g MgSO3 and 0.763 g H2O
babunello [35]

The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgSO₃ = 0.737g / 104.3g/mol = 0.007mol

Moles of H₂O = 0.763g / 18g/mol = 0.04 mol

Number of H₂O molecule = 0.04/0.007 = 5.7 = 6

So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

To know more about hydrate compound, visit the below link:

brainly.com/question/22411417

#SPJ1

6 0
2 years ago
Suppose there are two known compounds containing the generic elements X and Y. You have a 1.00-g sample of each compound. One sa
Lapatulllka [165]

I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y, for the following reason: 

If you look at the combining masses of X and Y in each of the two compounds, 

The first compound contains 0.25g of X combined with 0.75g of Y 
so the ratio (by mass) of X to Y = 1 : 3 

The second compound contains 0.33 g of X combined with 0.67 g of Y 
so the ratio (by mass) of X to Y = 1 : 2 

Now, you suppose to prepare each of these two compounds, starting with the same fixed mass of element Y ( I will choose 12g of Y for an easy calculation!) 

The first compound will then contain 4g of X and 12g of Y 
The second compound will then contain 6g of X and 12g of Y 

<span>The ratio which combined the masses of X and the fixed mass (12g) of Y
= 4 : 6 
<span>or 2 : 3 </span>

So, the ratio of MOLES of X which combined with the fixed amount of Y in the two compounds is also = 2 : 3 </span>

The two compounds given with the plausible formula must therefore contain the same ratio.

8 0
3 years ago
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