Yes. This is true because 4 subtracted from 8 is 8-4=4. The value you get from subtracting 4 from 8 equals the same value you would get if you were to take the value of 2 and square it. Both equal 4.
So the groups of angles that make a line (like 130 and i or p a and t) should equal 180. however, the triangles should also equal 180. so in this case for the top row, we know that 130+j=180. since 180-130=50 (i did the inverse of addition, subtraction), j=50. now let’s say for that triangle that your top two angle measures were the 50 we just found and the 70 you have written just as an assumption but i have no clue what you were actually given. since triangles angles must equal 180, 50+70+that angle =180. 50+70=120, so if we do the inverse of 180-120=60, we find out that the bottom angle is 60 degrees.
3/4= j-1/2
first to add 1/2 to both sides to solve for j
3/4 + 1/2= j
second you find a common denominator in order to add 3/4 and 1/2, the common denominator would be 4, you would have to change 3/4 at all because the denominator is already 4 but in order to make the denominator of 1/2, 4 you would have to multiply both the denominator and numerator by 2 so
3/4 + 2/4 = 5/4
so 5/4 =j
to check your answer you plug 5/4 in for j
3/4 = 5/4 -1/2
again you need to find a common denominator between 5/4 and 1/2 which again would be 4, and again you wouldn't change 5/4 but you would multiply both the numerator and the denominator of 1/2 so
3/4= 5/4-2/4
5-2= 3 and you would keep the 4 so
5/4 - 2/4 = 3/4
so j = 5/4
Answer:
The area in factored form is
.
The area in standard form is
.
Step-by-step explanation:
The area of a rectangle is length times width.
So the area here is (x+2)(x-5).
They are probably not looking for A=(x+2)(x-5) because it requires too little work.
They probably want A in standard form instead of factored form.
Let's use foil:
First x(x)=x^2
Outer: x(-5)=-5x
Inner: 2(x)=2x
Last: 2(-5)=-10
---------------------Adding together:
.
The area in factored form is
.
The area in standard form is
.
You answer is -25 your welcome