8% of 1000 = 80
8% of 1080 = 86.4
8% of 1166.4 = 93.31
8% of 1259.71 = 100.77
8% of 1360.48 = 108.8
$1469.28
Rounded: $1469
Answer:
If you have

The point (2,4) would be transformed to (1,1)
Step-by-step explanation:
If your compression is horizontal then the transformation you are making is the following

Therefore, if you have

The point (2,4) would be transformed to (1,1)
Answer:
I think 15 cubic meters might be wrong tho
Step-by-step explanation:
Answer:
![a=[2q^{2}r]](https://tex.z-dn.net/?f=a%3D%5B2q%5E%7B2%7Dr%5D)
![b=[3s^{2}t]](https://tex.z-dn.net/?f=b%3D%5B3s%5E%7B2%7Dt%5D)
Step-by-step explanation:
we have

we know that
![8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}](https://tex.z-dn.net/?f=8q%5E%7B6%7Dr%5E%7B3%7D%3D%282%5E%7B3%7D%29%28q%5E%7B2%7D%29%5E%7B3%7Dr%5E%7B3%7D%3D%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D)
![27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}](https://tex.z-dn.net/?f=27s%5E%7B6%7Dt%5E%7B3%7D%3D%283%5E%7B3%7D%29%28s%5E%7B2%7D%29%5E%7B3%7Dt%5E%7B3%7D%3D%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D)
therefore
![a=[2q^{2}r]](https://tex.z-dn.net/?f=a%3D%5B2q%5E%7B2%7Dr%5D)
![b=[3s^{2}t]](https://tex.z-dn.net/?f=b%3D%5B3s%5E%7B2%7Dt%5D)
substitute

![[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})](https://tex.z-dn.net/?f=%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D%20%2B%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D%3D%28%5B2q%5E%7B2%7Dr%5D%2B%5B3s%5E%7B2%7Dt%5D%29%28%5B2q%5E%7B2%7Dr%5D%5E%7B2%7D%20-%5B2q%5E%7B2%7Dr%5D%5B3s%5E%7B2%7Dt%5D%2B%5B3s%5E%7B2%7Dt%5D%5E%7B2%7D%29)
![[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])](https://tex.z-dn.net/?f=%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D%20%2B%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D%3D%28%5B2q%5E%7B2%7Dr%5D%2B%5B3s%5E%7B2%7Dt%5D%29%28%5B4q%5E%7B4%7Dr%5E%7B2%7D%5D%20-6%5Bq%5E%7B2%7Dr%5D%5Bs%5E%7B2%7Dt%5D%2B%5B9s%5E%7B4%7Dt%5E%7B2%7D%5D%29)
hope it helps!
Answer:
107.9 ft
Step-by-step explanation:
Imagine Kite is a point A. The person ,who keeps the string is point B.
The height of flying is AC=85 ft. So we have right triangle ABC :angle C=90 degrees, angle B is 52 degrees. Length of AB (triangle ABC hypotenuse) is the length of the string.
AB=AC/sinB=85/sin52=107.8665...=approx 107.9 ft