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3 years ago

1. Explain why the cold water and hot water in Part 1 moved the way they did within the tub of

Chemistry

1 answer:

neonofarm [45]3 years ago

5 0

Answer:

Cooling a substance causes molecules to slow down and get slightly closer together, occupying a smaller volume that results in an increase in density. Hot water is less dense and will float on room-temperature water. Cold water is more dense and will sink in room-temperature water.

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Which statements describe phase changes? Check all that apply. Particles in a liquid need to move more slowly in order to freeze

Kipish [7]

Answer: Statements (A), and (C) are correct.

Explanation:

The statements that are true are as follows.

Particles in a liquid need to move more slowly in order to freeze.

When a liquid freezes the molecules get attracted towards each other. This attraction of particles occurs slowly. Hence, this statement is true.

Attractive forces between the particles in a liquid are broken when a liquid boils.

When temperature is raised, the molecules in a liquid gains kinetic energy and start to move quickly in random directions. As a result, liquid state changes to gaseous state. Hence, this statement is true.

If the attractive force between gas molecules have to be increased, they should be moving slower instead because moving faster does not help attracting molecules together.

Hence, the statement particles in gas move fast enough to make more attractive forces when the gas condenses is not true.

4 0

3 years ago

Read 2 more answers

If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor

Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

=0.658 moles NaF

16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

8 0

3 years ago

1)Define potential Energy.

Margarita [4]

1. Potential Energy is stored energy a object has when it's not moving.

2. Potential Energy is it's highest on the first stage because as you see the roller coaster is bout to go down the tract which is going to higher the kinetic energy and lower the potential energy.

3. Kinetic Energy is the amount of energy a object has when it's in motion or moving.

4. Kinetic Energy is it's highest in the third stage after it's gone down the tract and potential energy fully decreased and it's at zero.

Remember that potential energy is stored energy so when a object is not moving in this case the roller coaster isn't moving on the first stage when its bout to go down the roller coaster. Kinetic energy is the amount of energy a object has when it's in motion so in this case the third stage would have the highest example of Kinetic energy because it's fully in motion and has no potential energy.

4 0

3 years ago

Which of the following molecules would you expect to have a dipole moment of zero? a,CH2 Ch3

Vadim26 [7]

Answer: The molecule $CH_{3}-CH_{3}$ is expected to have a dipole moment of zero.

Explanation:

The product of magnitude of the charge calculated in electrostatic units is called dipole moment.

Formula for dipole moment is as follows.

Dipole moment = Charge (in esu) $\times$ distance (in cm)

Non-polar molecules have zero dipole moment.

For example, $CH_{3}-CH_{3}$ is a non-polar molecule so its dipole moment is zero.

$H_{2}C=O$ is a polar molecule so it will have dipole moment.

$CH_{2}Cl_{2}$ is a polar molecule so it will have dipole moment.

$NH_{3}$ has nitrogen atom as more electronegative than hydrogen atom. So, net dipole moment will be in the direction of nitrogen atom.

Thus, we can conclude that the molecule $CH_{3}-CH_{3}$ is expected to have a dipole moment of zero.

4 0

3 years ago

Indicate the changes (increases, decreases, does not change) in its volume when the pressure undergoes the following changes at

Inga [223]

The question is missing information. Here is the complete question.

A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas. Match the words in the left with the column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

1. The pressure increases to 6.0 atm. The volume ________

2. The pressure drops to 0.40 atm. The volume _________

3. The pressure remains at 2.0 atm. The volume _________

Answer: 1. Decreases

2. Increases

3. Does not change

Explanation: According to the Ideal Gas Law, Pressure, Volume and Temperature of an ideal gas is related, as the following: PV = nRT.

In this case, since temperature (T) and amount of gas (n) are constant, the Boyle's Law can be used.

The law states that the volume of a given gas, under the conditios of temperature and amount of it are constant, is inversely proportional to the applied pressure: P₁.V₁ = P₂.V₂

For case 1.)

Initial P (P₁) = 2

Initial V (V₁) = V

Final P (P₂) = 6

P₁.V₁ = P₂.V₂

2.V = 6.V₂

V₂ = 1/3V

When the pressure increases to 6 atm, volume decreases by 1/3.

For case 2.)

P₁ = 2

V₁ = V

P₂ = 0.4

2.V = 0.4V₂

V₂ = 5V

When pressure drops to 0.4 atm, volume increases by 5.

For case 3.)

Since there are no change in the pressure, the volume is the same from the beginning, so does not change.

8 0

3 years ago