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2 years ago

1. Explain why the cold water and hot water in Part 1 moved the way they did within the tub of

Chemistry

1 answer:

neonofarm [45]2 years ago

5 0

Answer:

Cooling a substance causes molecules to slow down and get slightly closer together, occupying a smaller volume that results in an increase in density. Hot water is less dense and will float on room-temperature water. <u>Cold water is more dense and will sink in room-temperature water.</u>

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Suppose a 10.0 mL sample of an unknown

mote1985 [20]

The concentration of HCl is equal to 2.54mol/L.

<h3>Mole calculation</h3>

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

$M = \frac{mol}{v}$

Thus, to find the molarity of the sample, the following calculations must be performed:

$V_f = 10ml + 625ml = > 635ml$

$\frac{0.004mol}{xmol} =\frac{1000ml}{635ml}$

$x = 0.00254 mol$

So, 0.00254 moles were added per 10ml, so we can do:

$\frac{0.00254mol}{xmol}= \frac{10ml}{1000ml} \\x = 2.54mol/L$

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237

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2 years ago

Circle the solution with the highest concentration

choli [55]

Answer:

answer is option a..............

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2 years ago

Read 2 more answers

Determine the volume at STP of 36.8 g of nitrogen dioxide(NO2)

Anarel [89]

Answer:

17.92L

Explanation:

7 0

3 years ago

31. calculate the amount of energy released as heat by the freezing of 13.3 g of a liquid substance, given that the substance ha

spin [16.1K]

From the calculations, the heat of fusion of the substance is 0.73 kJ

<h3>What is is the heat of freezing?</h3>

The heat of freezing is the energy released when the substance is converted from liquid to solid.

Now we know that the molar mass of the substance is 82.9 g/mol hence the number of moles of the substance is; 13.3 g /82.9 g/mol = 0.16 moles

Now the heat of fusion shall be;

H = 4.60 kj/mol * 0.16 moles

H = 0.73 kJ

Learn more about freezing:brainly.com/question/3121416

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1 year ago

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,

gayaneshka [121]

Answer:

B > D > C > A

Explanation:

For the first law of the thermodynamics, the total energy variation in a process is:

ΔU = Q - W

Where Q is the heat, and W the work. If the system loses heat, Q < 0, if it absorbs heat, Q>0. If work is done in the system (volume decreases), W < 0, if the system does the work (volume increases), W > 0.

A. If the surroundings get colder, the system is absorbing heat, so Q>0, and the system decreases in volume so W < 0 :

ΔU = +Q - (-W) = +Q + W (absorbs a higher energy)

B. If the surroundings ger hotter, the system is losing heat, so Q<0, and the system expands, so W>0:

ΔU = -Q -W (loses higher energy)

C. Surroundings get hotter, Q<0, and the system decreases in volume, W<0

ΔU = - Q + W = 0 (magnitude of heat and work is similar)

D. Surroundings get hotter, Q<0, and the system is not changing in volume, W = 0.

ΔU = -Q (loses energy)

For the most released (more negative) for the most absorbed (most positive):

B > D > C > A

3 0

2 years ago