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2 years ago

13

1. Explain why the cold water and hot water in Part 1 moved the way they did within the tub of

1 answer:

neonofarm [45]2 years ago

5 0

Answer:

Cooling a substance causes molecules to slow down and get slightly closer together, occupying a smaller volume that results in an increase in density. Hot water is less dense and will float on room-temperature water. <u>Cold water is more dense and will sink in room-temperature water.</u>

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I turn the Ritz into a poor house

Ket [755]

Low life?- i’m pretty sure

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2 years ago

A student has two compounds in two separate bottles but with no labels on either one. One is an unbranched alkane, octane, C8H18

Aleks [24]

Answer:

a) both substances are insoluble in water

b) both substances are soluble in ligroin

c) both substances suffer combustion, octane produces more CO₂ than hexene.

d) both substances are less dense than waterl, with hexene having the lowest density.

e) only hexene would react with bromine

f) only hexene would react with permanganate

Explanation:

a) both substances are non-polar and water is polar

b) both substances are non-polar and lingroin is non-polar

c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O

C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

d) water = 997 kg/m³

ocatne = 703 kg/m³

hexene = 673 kg/m³

e) bromine test is used to detect unsaturations

f) permanganate test is used to detect unsaturations

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3 years ago

How many neutrons are present in an atom of element C?

Stolb23 [73]

Answer:

six neutrons

Explanation:

there are six neutrons present in C Carbon

4 0

2 years ago

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While exploring a coal mine, scientists found plant fossils in the ceiling of the mine which had been preserved by an earthquake

ale4655 [162]

Answer:

11552.45 years

Explanation:

Given that:

Half life = 5730 years

$t_{1/2}=\frac{\ln2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{5730}\ years^{-1}$

The rate constant, k = 0.00012 years⁻¹

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given that:

The rate constant, k = 0.00012 years⁻¹

Initial concentration $[A_0]$ = 160.0 counts/min

Final concentration $[A_t]$ = 40.0 counts/min

Time = ?

Applying in the above equation, we get that:-

$40.0=160.0e^{-0.00012\times t}$

$e^{-0.00012t}=\frac{1}{4}$

$-0.00012t=\ln \left(\frac{1}{4}\right)$

$t=11552.45\ years$

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2 years ago

How many moles are found in 133 g of Mg3 N2

konstantin123 [22]

Magnesium nitride weighs 100.95 g/mol

133/100.95 = 1.32 mols

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2 years ago

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