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FromTheMoon [43]
4 years ago
9

Once again if anyone could help, I would really appreciate your help! Thank you ❤️

Chemistry
1 answer:
Nikolay [14]4 years ago
6 0

Answer:

D

Explanation:

I explained how to do it on your other problem so look there :)

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find the empirical formula of the compound containing 11.3% of carbon, 43.4 % of sodium 45.3 % of oxygen ​
eduard

Answer:

CNa203

Explanation:

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3 years ago
In the wave-mechanical model, an orbital is a region of space in
Ilia_Sergeevich [38]
The answer is (1). Quantum mechanics views electron orbitals not as fixed circular paths or defined boundaries, but as probablility distributions that represent the probability of finding an electron at any point in space around the nucleus. For simplicity, discrete "boundaries" are often drawn enclosing the area where electrons should be found 90% of the time.
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3 years ago
How did atomists describe fire?
Diano4ka-milaya [45]
They explained it up be one of the four naturally occurring elements
5 0
3 years ago
The vapor pressure of pure water at 250C is 23.77 torr. What is the vapor pressure of water above a solution that is 1.500 m glu
Olegator [25]

Answer:

Vapor pressure of water = 23.14torr

Explanation:

When you made a solution, vapor pressure decreases following Raoult's law:

P_{solution} = X_{solvent} P_{solvent}

<em>Where P is vapor pressure and X mole fraction</em>

As vapor pressure of water is 23.77torr we must find the mole fraction of water knowing the solution is 1.500m glucose (That is 1.500 moles of glucose per kg of water = 1000g of water).

1000g of H₂O are, in moles (Molar mass: 18.02g/mol):

1000g H₂O ₓ (1mole / 18.02g) = 55.5 moles of H₂O.

As we know now the solution contains 55.5 moles of water and 1.5 moles of glucose. Thus, mole fraction of water (Solvent) is:

X_{H_2O} = \frac{55.5molesH_2O}{55.5molesH_2O + 1.5 molesGlucose} = 0.9737

Replacing in Raoult's law, pressure of water above the solution is:

P_{solution} = X_{solvent} P_{solvent}

P_{solution} = 0.9737*23.77torr

<h3>Vapor pressure of water = 23.14torr</h3>
7 0
3 years ago
Calculate the moles and grams of solute in each solution. D. 2.0 L of 0.30M Na2SO4. I already have A, B, and C. Thanks!
e-lub [12.9K]
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol


Find the molar mass
2Na = 23 * 2 = 46 grams
1S   = 32 * 1 = 32 grams
O4   = 16 * 4 = 64 grams
Total =            142 grams / mol

Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???

given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams. 

85.2 are in a 2 L solution that has a concentration of 0.6 mol/L


4 0
3 years ago
Read 2 more answers
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