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UNO [17]
4 years ago
7

These questions are based on the attached photo. The experiment is about burning magnesium metal with oxygen. 1. Write the balan

ced chemical equation for the reaction you are performing. 2. Calculate the mass of magnesium metal used in each trial. o Trial 1: o Trial 2: 3. Calculate the actual yield of magnesium oxide for each trial. o Trial 1: o Trial 2: 4. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial. o Trial 1: o Trial 2: 5. Determine the percent yield of MgO for your experiment for each trial. o Trial 1: o Trial 2: 6. Determine the average percent yield of MgO for the two trials. Your company currently uses a process with a similar cost of materials that has an average percent yield of 91 percent. If the average percent yield of this process is higher than that, this could save the company money. What is your recommendation to the company? Please support your recommendation using your data, calculations, and understanding of stoichiometry gathered from this lab.
Chemistry
1 answer:
vazorg [7]4 years ago
5 0

​Answer:

Write the balanced chemical equation for the reaction you are performing.

2Mg+ O2 → 2MgO

2.​Calculate the mass of magnesium metal used in each trial.

o Trial 1: 26.945-26.691

Mg metal= 0.254 g

o Trial 2: 26.948-26.691

Mg metal= 0.257 g

3.​Calculate the actual yield of magnesium oxide for each trial.

o Trial 1: 27.108-26.691

MgO= 0.417 g

o Trial 2: 27.110-26.691

MgO= 0.419 g

4.​Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.

o Trial 1: 0.254g*1 mol/24.305g Mg*2mol MgO/2mol Mg*40.305/1g MgO

0.421g MgO

o Trial 2: 0.257g*1 mol/24.305g Mg*2mol MgO/2mol Mg*40.305/1g MgO

0.426g MgO

5.​Determine the percent yield of MgO for your experiment for each trial.

o Trial 1: 0.417/0.421*100= 99.1%

o Trial 2: 0.419/0.426*100= 98.4%

6.​Determine the average percent yield of MgO for the two trials.

99.1+98.4= 98.8%

Questions and Conclusions:

1. Describe the process that was used in this lab to create magnesium oxide, specifically identifying the type of chemical reaction. Explain why the product had a higher mass than the reactant, and how this relates to conservation of matter.

Mg was heated with O2 to produce MgO. The reaction used to create magnesium oxide was oxidation reaction. It was an oxidation reaction because Mg loss electrons to react with O, magnesium gained O and oxidized to MgO. The product had a higher mass than the reactant because the reactant bonded to O and formed MgO, so the product had a higher mass due to the gain of O atom over the reactant Mg. This relates to conservation of matter, because the mass of products must be the same as the mass of reactants.

2. What sources of error may have contributed to the percent yield not being 100 percent? Think about things that may have led to inaccurate measurements or where the mass of the product could have been lost if this experiment was conducted in a physical laboratory.

Temperature of the Bunsen burner, Magnesium scraped off by steel wool.

3. When conducting this experiment, some procedures call for heating the substance several times and recording the mass after each heating, continuing until the mass values are constant. Explain the purpose of this process and how it might reduce errors.

It might reduce errors by keeping track of all the measurements of weight

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how many grams of zinc will be formed if 32 G of copper reacts with zinc nitrate copper 1 nitrate is the other product ​
arsen [322]

Answer:

Mass = 32.69 g

Explanation:

Given data:

Mass of copper = 32 g

Mass of zinc formed = ?

Solution:

Chemical equation:

Cu + Zn(NO₃)₂     →       Cu(NO₃)₂ + Zn

Number of moles of copper:

Number of moles = mass/molar mass

Number of moles = 32 g/ 63.55 g/mol

Number of moles = 0.5 mol

now we will compare the moles of zinc with copper.

           Cu          :           Zn

            1            :            1

          0.5          :         0.5

Mass of Zn:

Mass = number of moles × molar mass

Mass = 0.5 mol  × 65.38 g/mol

Mass = 32.69 g

6 0
3 years ago
Acids hydrolyze or dissolve in solutions to form what? acids hydrolyze or dissolve in solutions to form what? hydroxide ions sol
nikklg [1K]
<h3>Answer:</h3>

                      Acids hydrolyze or dissolve in solutions to form <u>Protons</u>.

<h3>Explanation:</h3>

                      Acid are defined according to three different theories and concepts.

                       i)  Arrhenius Concept

                       ii) Lowry Bronsted Theory

                      iii) Lewis Theory

According to Arrhenius Concept of Acid and Base, "Acid is any specie which when dissolved in water ionizes to produce H⁺ ions".

Example:

                                  HCl    →    H⁺₍aq₎  +  Cl⁻₍aq₎

                                  H₂SO₄    →    2 H⁺₍aq₎  +  SO₄²⁻₍aq₎

Proton (H⁺):

                   Hydrogen atom with atomic mass of 1 amu contains one proton and one electron in its first shell. When this single electron is removed from hydrogen atom it is left with only one proton hence, H⁺ is called proton.

Hydrolysis:  

                 In simple, hydrolysis is that reaction in which water molecules are utilized to breakdown a chemical compound.

<h3>Conclusion:</h3>

                     Hence, we can conclude that Arrhenius Acids when added to water are being hydrolyzed by water molecule and yield H⁺ (proton) along with corresponding negative specie.

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What might be your reference point other than yourself if you determine that the dog is not moving?
Anettt [7]

Complete statement:

Suppose your in the car with the dog. What might be your reference point other than yourself if you determine the the dog is not moving.

Answer:

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Explanation:

A reference point is a place or object used for comparison to determine whether something is in motion. If the dog is in the car with me, and the reference point would be the car other than me. For a car, the dog is also not in the motion.

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svetlana [45]
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Potassium bromide has a melting point of 734°C.
dezoksy [38]

Answer:

The stronger the intermolecular forces are, the more energy is required, so the higher the melting point is. Many intermolecular forces depend on how strongly atoms in the molecule attract electrons — or their electronegativity.

kamsahamnida

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3 0
3 years ago
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