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ExtremeBDS [4]
3 years ago
11

WILL GIVE POINTS AND BRAINLIEST Question: Number of H− ions in 5.22 g of SrH2

Chemistry
1 answer:
Sophie [7]3 years ago
4 0

Answer:

moles H = 2 x 0.0649=0.130

ions = 0.130 x 6.02 x 10^23=7.81 x 10^22

Explanation:

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How do you write the formula for potassium hydroxide
makvit [3.9K]

KOH that or H3C-CH2-OH

7 0
3 years ago
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Which subatomic particle can change the molecular geometry of a molecule?
emmainna [20.7K]

Answer:

Electrons

Explanation:

According to the Valence Shell Electron Pair Repulsion Theory (VSEPR), the geometry of a molecule depends on the number of electron pairs (regions of electron density) on the central atom of the molecule. Electron pairs on the valence shell of the molecule tend to position themselves as far apart in space as possible to minimize repulsion between them. Hence, the orientation of these electron pairs is the ultimate determinant of the observed geometry of a molecule.

Lone pairs of electrons cause more repulsion than bond pairs of electrons on the central atom of a molecule. Hence when the central atom of a molecule contains lone pairs of electrons, the molecular geometry is usually distorted from the expected geometry on the basis of VSEPR theory.

Hence, electrons are the subatomic particles which are responsible for any change in the observed molecular geometry of a molecule.

6 0
3 years ago
What is the volume of stank of nitrogen that contains 17 moles of nitrogen at 34 C under 12,000Pa?
Otrada [13]

Answer:

3626.76dm³

Explanation:

Given parameters:

Number of moles of Nitrogen in tank = 17moles

Temperature of the gas = 34°C

Pressure on the gas = 12000Pa

Unkown:

Volume of the tank, V =?

Converting the parameters to workable units:

We take the temperature from °C to Kelvin

K = 273 +  °C  = 273 + 34 = 307k

Taking the pressure in Pa to atm:

101325Pa = 1atm

12000Pa = 0.118atm

Solution:

To solve this problem, we employ the use of the ideal gas equation. The ideal gas law combines three gas laws which are the Boyle's law, Charles's law and the Avogadro's law.

            It is expressed as PV = nRT

The unknown is the Volume and we make it the subject of the formula

             V = \frac{nRT}{P}

Where R is called the gas constant and it is given as 0.082atmdm³mol⁻¹K⁻¹

Therefore  V = \frac{17 x 0.082 x 307 }{0.118} = 3626.76dm³

3 0
3 years ago
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What mass of octane must be burned in order to liberate 5270 kj of heat? δhcomb = -5471 kj/mol?
katrin2010 [14]
As,
                           5471 kJ heat is given by  =  1 mole of Octane
Then,
                    5310 kJ heat will be given by  = X moles of Octane

Solving for X,
                                  X  =  (5310 kJ × 1 mol) ÷ 5471 kJ

                                  X  =  0.970 moles of Ocatne

So, 0.970 moles of Octane will liberate 5310 kJ energy. Now changing moles to mass,
As,
                                  Moles  =  mass / M.mass
Or,
                                  Mass  =  Moles × M.mass
Putting values,
                                  Mass  =  0.970 mol × 114.23 g/mol

                                  Mass  =  110.83 g of Octane
6 0
3 years ago
Give the half-equation for the reaction at the anode, during
oee [108]
The answer would be B
3 0
3 years ago
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