Answer:
Explanation:
- For the balanced reaction:
<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s).</em>
It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.
- Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:
no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.
- Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:
<em><u>Using cross multiplication:</u></em>
4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.
0.64 mol of Fe is needed to react with → ??? mol of O₂.
∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.
- Finally, we can get the volume of oxygen using the information:
<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>
<em></em>
<em><u>Using cross multiplication:</u></em>
1 mol of O₂ occupies → 22.4 L, at STP conditions.
0.48 mol of O₂ occupies → ??? L.
∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.
an element's name, chemical symbol, atomic number, atomic mass.
IDK what you are even asking for
Answer:
sorry but i am doing this for point
Explanation:
how do I complete this column graph of the number of conduct vs the number of
Hiii
3. describe the physical characters that can be observed: phenotype
6. a specific characteristic of an organism: trait
7. a section of DNA that provides instructions for specific traits: genes
8. allele expressed in the phenotype even if only one copy is present in the genotype: dominant
hope this helped :)
pH of the acetyl choline solution before incubation = 7.65
![[H_{3}O^{+}]=10^{-7.65}=2.24*10^{-8}M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D10%5E%7B-7.65%7D%3D2.24%2A10%5E%7B-8%7DM)
pH of the solution after incubation = 6.87
![[H_{3}O^{+}]=10^{-6.87}=1.35*10^{-7}M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D10%5E%7B-6.87%7D%3D1.35%2A10%5E%7B-7%7DM)
The difference in concentration of hydronium ion before and after incubation
=
-
=
This difference in hydronium ion concentration can be attributed to the increase in the concentration of acetic acid, which is formed when acetylcholine is hydrolyzed by acetycholinesterase. The mole ratio of acetylcholine to acetic acid is 1:1.
Therefore the moles of acetylcholine = 
