Answer:
x=25/3 & y=125/3
Step-by-step explanation:
Let first number be x
Second number be y
x+y=50
y=5x
=>x+5x=50
=>6x=50
=>x=50/6
=>x=25/3
Look at the paper for solutions.
If A is QIV, then 3π/2 ≤A≤2π;
we have to find out in what quadrant is A/2
(3π/2)/2≤A/2≤(2π)/2 ⇒ 3π/4≤A/2≤π
We can see that A/2 will be in QIII; therefore the sec (A/2) will be negative (-).
1) we have to calculate cos (A/2)
Cos (A/2)=⁺₋√[(1+cos A/2)/2]
We choose this formula: Cos (A/2)= -√[(1+cos A/2)/2], because sec A/2 is in quadrant Q III, and the secant (sec A/2=1/cos A/2) in this quadrant is negative.
Cos (A/2)=-√[(1+cos A)/2]=-√[(1+(1/2)]/2=-√(3/4)=-(√3)/2.
2) we compute the sec (A/2)
Data:
cos (A/2)=-(√3)/2
sec (A/2)=1/cos (A/2)
sec (A/2)=1/(-(√3)/2)=-2/√3=-(2√3)/3
Answer: sec (A/2)=-(2√3)/3
106,127,129,132,135,138,140,158
132 + 135 = 267
267/2 = 133.5
Median is 133.5
We are given with 90<x<180 degrees and asks for the value of sin(x/2), cos(x/2) and tan(x/2). We just substitute the maximum and minimum angle to the equations. sin (180/2) is equal to 1 and sin (90/2) is equal to

to 1. cos (x/2) is equal to 0≤y≤<span>

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