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GuDViN [60]
3 years ago
10

Spears Co. will receive SF1,000,000 in 30 days. Use the following information to determine the total dollar amount received (aft

er accounting for the option premium) if the firm purchases and exercises a put option: Exercise price = $.61 Premium = $.02 Spot rate = $.60 Expected spot rate in 30 days = $.56 30-day forward rate = $.62
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

Step-by-step explanation

Given that,

Spear Co will receive SF1,000,000 after 30days

Exercise price = $.61

Premium = $.02

Spot rate = $.60

Expected spot rate in 30 days = $.56

30-day forward rate = $.62

The total dollar receive will be

(Exercise Price -premium)× received

($.61 − $.02) × SF1,000,000 = $590,000

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Lucy bought three books at a bookstore. Here are their prices (in dollars).
Valentin [98]

Answer:

41.82$

Step-by-step explanation:

The prices are

7.58$, 16$, 18.24$.

To get the total of all what Lucy bought, You add the prices altogether.

That is,

18.24$

+16.00$

+<u>0</u><u>7</u><u>.</u><u>5</u><u>8</u><u>$</u>

41.82$

The total amount of what Lucy bought is 41.82$

8 0
2 years ago
A weight lifter lifts a setof 1250kg weights a vertical distance of 2m in a weight lifting contest what potential energy do the
nikitadnepr [17]

Answer:

<u>U = mgh = (1250 kg)(9.8 m/s2)(2m) = ? J</u>

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3 0
3 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
Click on the words to go to the picture
balu736 [363]
B) 196 cubic cm or something like that... First you multiply 7x5x14=490... then you divide 490/5 because you're working in fifths and get 98... the white is only two-fifths so you multiply 98 times 2 and get 196
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3 years ago
In a school with 615 students, 18 classes are formed. If the classes are equal in size, and far as possible, how many classes ar
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The answer is c or 2!
6 0
3 years ago
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