If <em>v</em> is the truck's final velocity, then
<em>v</em>² - (2.0 m/s)² = 2 * (2.00 m/s²) * (400.0 m)
<em>v</em>² = 1604 m²/s²
<em>v</em> = 40.05 m/s ≈ 40 m/s
Answer
given,
V = 2 L
the left is an ideal gas at P = 100 k Pa and T = 500 K
mass is constant
Pressure is same because it's not changing due to process
m = 1.39 x 10⁻³ Kg
Answer:
he tail of the arrow moves a distance of 0.5 m as the arrow is shot. yare yare daze
Explanation:
Answer:
(a) 1.2 rad/s
(b) 1.8 rad
Explanation:
Applying,
(a) α = (ω-ω')/t................ Equation 1
Where α = angular acceleration, ω = final angular velocity, ω' = initial angular velocity, t = time.
From the question,
Given: α = 0.40 rad/s², t = 3 seconds, ω' = 0 rad/s (from rest)
Substitute these values into equation 1
0.40 = (ω-0)/3
ω = 0.4×3
ω = 1.2 rad/s
(b) Using,
∅ = ω't+αt²/2.................. Equation 2
Where ∅ = angle turned.
Substitutting the values above into equation 2
∅ = (0×3)+(0.4×3²)/2
∅ = 1.8 rad.
