The answer is 4.0 kg since the flywheel comes to rest the
kinetic energy of the wheel in motion is spent doing the work. Using the
formula KE = (1/2) I w².
Given the following:
I = the moment of inertia about the
axis passing through the center of the wheel; w = angular velocity ; for the
solid disk as I = mr² / 2 so KE = (1/4) mr²w². Now initially, the wheel is spinning
at 500 rpm so w = 500 * (2*pi / 60) rad / sec = 52.36 rad / sec.
The radius = 1.2 m and KE = 3900 J
3900 J = (1/4) m (1.2)² (52.36)²
m = 3900 J / (0.25) (1.2)² (52.36)²
m = 3.95151 ≈ 4.00 kg
The natural light display called aurora borealis is located in the northern
hemisphere.
There are two types of aurora which are called aurora borealis and aurora
australis. The aurora borealis is located in the Northern hemisphere while
the aurora australis is located in the Southern hemisphere.
They receive their energy through the interaction of charged particles
on the Sun and Earth to produce the light display. An example
of the interaction involves solar wind with atoms of the upper atmosphere.
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Answer:
Where's the question or the picture???
