The strength of the electric field is 5 N/C
Explanation:
The magnitude of the electric field produced by a single-point charge is given by:
where
is the Coulomb's constant
Q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the charge producing the field
r = 100 m is the distance from the charge at which we want to calculate the field
Substituting into the equation, we find the s trength of the electric field:
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1
2 4. 5 4 5
+3 0 7. 3 0 0
——————
3 3 1 8 4 5
line up the decimal points and add.
hope this helps!
Answer:
comparing the anatomy of organisms
Explanation:
Basically, Rocks are the solid evidence used to date the earth.
Due to the changing in the genetic make up of organisms,the anatomy of organisms is not a reliable evidence to date the earth.
The velocity of the object is zero (the object is at rest)
Explanation:
A position vs time graph represents the motion of an object; in particular:
- The position of the object x(t) is represented on the y-axis
- The time t is represented on the x-axis
For a position-time graph, the slope of the graph is given by
where
is the change in position
is the change in time
However, we see that this is equivalent to the definition of velocity:
Therefore, the slope of a position-time graph is equivalent to the velocity of the object.
And so, a horizontal segment on a position vs time graph means that the object has zero velocity (because the slope is zero).
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Answer:
A) 10 m/s
Explanation:
We know that according to conservation of momentum,
m1v1 + m2v2 = m1u1 + m2u2 ..............(equation 1)
where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.
From the given data
If truck and car are two bodies
truck : m1 = 2000 Kg v1 = 5 m/s u1 = 0
car : m2 = 1000 kg v2 = 0 u2 = ?
final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.
substituting the values in equation 1, we get
(2000 x 5) + 0 = 0 + (1000 x u2)
u2 = 
x 5
= 10 m/s
Hence after collision, car moves at a velocity of 10 m/s
