Use PV = mRT/M and solve for R. R = PVM/RT. Since you have the same gas under two sets of conditions then you can write
<span>P1V1M1/m1T1 = P2V2M2/m2T2 </span>
<span>Since P, M and T are constant, the equation becomes </span>
<span>V1/m1 = V2/m2 </span>
<span>Now plug in your values and solve for V2</span>
Answer:
I think the answer is 138.11 gram
Explanation:
Answer:
8
Explanation:
the number before the abbrviation for calcium (Ca) shows how many calcium there is.
Answer:

<em><u>Step by step explanation</u></em><em><u>:</u></em>
<em>Given:</em>
Mass of given sample (m) = 2.50 g
Initial temperature (T1) = 25°C
Final temperature (T2) = 20°C
Heat Energy Q = 12 cal
<em>T</em><em>o </em><em>find:</em>
<em>
</em>
<em>Solution</em><em>:</em>
We know that,
<em>Specific</em><em> </em><em>heat</em> <em>of </em><em>any </em><em>substance </em><em>is </em><em>directly</em><em> </em><em>proportional</em><em> </em><em>to </em><em>the </em><em>mass </em><em>and </em><em>change </em><em>in </em><em>temperature.</em>
Represented by equation,

Where,
<em>Q = Heat Energy</em>
<em>m = mass of given sampl</em><em>e</em>
<em>c = specific heat</em>
<em>∆T = change in </em><em>temperature</em>
Substituting corresponding values,
<em>
</em>
We also know that,

multiplying above answer by 4.184,

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