All categories

3 years ago

Explain the purpose of the heat exchanger in the nuclear power plant.

Chemistry

2 answers:

Ymorist [56]3 years ago

5 0

Answer:

A heat exchanger is device which is designed to transfer heat from one matter to another. In nuclear power plants, these heat exchangers are used to pass heat from primary system to the secondary system. In the process they produce steam from water, they are also called steam generators or pressurized water reactors.

My name is Ann [436]3 years ago

3 0

Answer:

yeah someone explain

Explanation:

tttttttttt%ttttttt

You might be interested in

What is the molarity of 2.3 mol of Kl dissolved in 0.5 L of water

Nastasia [14]

Answer:

$4.6\,\,moL\,\,L^{-1}$

Explanation:

Molarity refers to a measure of concentration.

Molarity = moles of solute/Litres of solution

Molarity refers to number of moles of solute present in this solution.

In order to find a solution's molarity, use value for the number of moles of solute and the total volume of the solution expressed in liters

As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,

Molarity = $\frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}$

4 0

4 years ago

When 100.g Mg3N2 reacts with 75.0 g H2O, what is the maximum theoretical yield of NH3?

Temka [501]

Answer : The correct option is, 23.6 g

Explanation : Given,

Mass of $Mg_3N_2$ = 100.0 g

Mass of $H_2O$ = 75.0 g

Molar mass of $Mg_3N_2$ = 101 g/mol

Molar mass of $H_2O$ = 18 g/mol

First we have to calculate the moles of $Mg_3N_2$ and $H_2O$ .

$\text{Moles of }Mg_3N_2=\frac{\text{Given mass }Mg_3N_2}{\text{Molar mass }Mg_3N_2}$

$\text{Moles of }Mg_3N_2=\frac{100.0g}{101g/mol}=0.990mol$

and,

$\text{Moles of }H_2O=\frac{\text{Given mass }H_2O}{\text{Molar mass }H_2O}$

$\text{Moles of }H_2O=\frac{75.0g}{18g/mol}=4.17mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$Mg_3N_2(s)+6H_2O(l)\rightarrow 3Mg(OH)_2(aq)+2NH_3(g)$

From the balanced reaction we conclude that

As, 6 moles of $H_2O$ react with 1 mole of $Mg_3N_2$

So, 4.17 moles of $H_2O$ react with $\frac{4.17}{6}=0.695$ moles of $Mg_3N_2$

From this we conclude that, $Mg_3N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2O$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 6 moles of $H_2O$ react to give 2 moles of $NH_3$

So, 4.17 moles of $H_2O$ react to give $\frac{2}{6}\times 4.17=1.39$ mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

Molar mass of $NH_3$ = 17 g/mole

$\text{ Mass of }NH_3=(1.39moles)\times (17g/mole)=23.6g$

Therefore, the maximum theoretical yield of $NH_3$ is, 23.6 grams.

4 0

3 years ago

What happens to the reactivity of nonmetals within a group from top of the group to the bottom?

andreev551 [17]

As you go down a group, the atoms get bigger. The bigger the atom, the more unstable it is. The more unstable it is, the more reactive the atom will be. So, as you go down a group, the nonmetals will become more reactive.

6 0

4 years ago

If D+2 would react with E-1, what do you predict the formula to be. A) DE B)D2E C)DE2 D) D2E2

allochka39001 [22]

All you need to do the cross the charges and put it as suffixes.

D+2 + E-1 ----> DE2

answer is C

5 0

3 years ago

Read 2 more answers

In covalent bonds atmosphere share electrons so that?

professor190 [17]

The electons are in the atmosphere

6 0

3 years ago