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3 years ago

What is 4.2345 rounded to the nearest tenth

Mathematics

2 answers:

MAVERICK [17]3 years ago

7 0

Answer to question:

4.2

quester [9]3 years ago

5 0

Answer:

4.2

Step-by-step explanation:

The tenth spot would be the number right after the decimal. The number in the hundredths spot is the one that determines what happens to the number in the tenths spot.

If the number in the hundredths is 5 or more, you would round the number in the tenths spot up one.

If the number in the hundredths spot is 4 or less, you would keep the same number in the tenths spot.

Since the number in the hundredths spot is 3, you would leave the number in the tenths place the same (2).

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8+n the answer is 45

liq [111]

Answer:

n=37

Step-by-step explanation:

45-8=37

6 0

3 years ago

Read 2 more answers

A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t

Tanya [424]

Answer:

Step-by-step explanation:

5.25 - 2.625 = 2.625 inches

3 0

3 years ago

A bag contains red and blue marbles, such that the probability of drawing a blue marble is 3/8

aleksklad [387]

Answer:

9/64

Step-by-step explanation:

The probability that the marble on the first draw is blue is 3/8.

The probability that the marble on the second draw is blue is also 3/8.

So the probability that both are blue is:

3/8 × 3/8 = 9/64 ≈ 14%

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3 years ago

What is the difference between a trapezoid and a rhombus?

Leya [2.2K]

Your answer is C bro

7 0

2 years ago

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$

$2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i$

$Used:\ (a+b)(a-b)=a^2-b^2$

6 0

3 years ago