Explanation:
From the given figure,
Mass of ball A is 4.9 kg and its initial speed is 8 m/s.
Mass of ball B is 1.9 kg and its initial speed is 14 m/s.
Mass of ball C is 0.7 kg and its initial speed is 2 m/s.
We need to find the final speed of the balls 1 s after being thrown. They all are thrown upward under the action of gravity. The equation of motion is : v = u -gt, g = 10 m/s²
For ball A,
v = 8-10(1) = = -2 m/s (downward)
For B,
v = 14-10(1) = 4 m/s (upward)
For C,
v = 2-10(1) = -8 m/s (downward)
It means the ranking is B>A>C i.e. the speed of ball B is the most and that of C is least.
All the balls are moving under the action of gravity. It would mean that the acceleration for all balls is same i.e. 10 m/s²
Answer:
a. -5,4
b. 28
Explanation:
(see how to solve in pic)
Answer:
Explanation:
Given that,
AC frequency of 2.3KHz
f=2.3×10³Hz
Vrms produce is
Vrms=1.5V
Current rms
Irms= 31mA
The capacitor is reconnected to a generator of frequency
f=4.8KHz =4800Hz
The current rms becomes
Irms= 85mA
Vrms=?
Solution
First genrator
The capacitive reactance is given as
Xc=Vrms/Irms
Xc=1.5/31×10^-3
Xc=48.39 ohms
Now, to know the capacitance of the capacitor
Xc=1/2πfC
Then,
C=1/2πfXc
So,
C=1/2×π×2300×48.39
C=1.43×10^-6C
C=1.43μF
Note: the capacitance of the capacitor did not change,
Now for generator two.
The reactance are given as
Xc=1/2πfC
Xc=1/2×π×4800×1.43×10^-6
Xc=23.19ohms
Then,
Vrms2=Irms2 ×Xc
Vrms2=85×10^-3×23.19ohms
Vrms2=1.97V
Vrms2=1.97Volts
Answer:
g = 1.64m/s²
Explanation:
1.5m in 0.078s
V = 15 / 0.078
= 19.23m/s
Tension = mg
μ = 3.10 × 10⁻⁴
T = V²μ
mg = V²μ
g = V²μ / m
g = ((19.23)²(3.10 × 10⁻⁴)) / (0.070)
g = 1.64m/s²
