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3 years ago

HELPPPPP ASAPPP!!!!!!!

Physics

1 answer:

bezimeni [28]3 years ago

4 0

Answer:

The tension T in each of the cables, T = 98 N

Explanation:

Given,

The mass of the loudspeaker, m = 20.0 Kg

The suspended distance of the loudspeaker, d = 2.20 m

The length of each cable, l = 2.9 m

The tension experienced by the cable is given by the formula,

T = mg + ma newton

Where,

g - acceleration due to gravity

a-acceleration produced by the stretched cable

Since the stretched cable and loudspeaker is not moving, then the tension force acting on the cable is equal to the force of gravity.

T = mg newton

Substituting the values in the above equation

T = 20

= 20.0 Kg x 9.8 m/s²

= 196 N

This force is equally supported by the two cables, then the tension in each cable is

T = 196 N / 2

= 98 N

Hence, the tension T in each of the cables, T = 98 N

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2 years ago

Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800c. Mavis and Stanley start timers at zero when t

yawa3891 [41]

Answer:

a) $x=2*10^{9} m$ and $t=8.35 s$

b) t = γt', so it is 8.35 s.

Explanation:

a) The equation of Lorentz transformations is given by:

$x=\gamma(x'+ut')$

x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.

x' = 0
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$\gamma=\frac{1}{\sqrt{1-(0.800c/c)^{2}}}$

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Now, to find t we apply the same analysis:

$t=\gamma(t'+\frac{ux'}{c^{2}})$

but as x'=0 we just have:

$t=\gamma(t')$

$t=1.67*5.00=8.35 s$

b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.

I hope it helps you!

5 0

2 years ago

Read 2 more answers