Answer:
The samples specific heat is 14.8 J/kg.K
Explanation:
Given that,
Weight = 28.4 N
Suppose, heat energy 
Temperature = 18°C
We need to calculate the samples specific heat
Using formula of specific heat
Where, m = mass
c = specific heat
= temperature
Q = heat
Put the value into the formula
Hence, The samples specific heat is 14.8 J/kg.K
Answer:
Description: When a geosynchronous satellite is placed directly above the Equator with a circular orbit and angular velocity identical to that of the Earth, the satellite is known as a geostationary satellite
Explanation:
These satellites appear to be stationary above a particular point which is due to the synchronization. This type of satellite provides a distinct benefit of fixing the receiving antennas at one place, hence making them more economical than regular tracking antennas. Over the years, these satellites have helped in revolutionizing the global communications, weather forecasting and television broadcasting. When the orbit of a geosynchronous satellite is not aligned directly over the equator, the orbit is known as an inclined orbit.
Answer:
6 and 8
Explanation:
The different positions of the moon, as seen from Earth, reflect how much light is being reflected off the moon from the sun.
Position 1 indicates the 3rd Quarter.
Position 2 indicates the Waning Gibbous.
Position 3 indicates the Full Moon.
Position 4 indicates the Waxing Gibbous.
Position 5 indicates the 1st Quarter.
Position 6 indicates the Waxing Crescent.
Position 7 indicates the New Moon.
Position 8 indicates the Waning Crescent.
You would read the diagram counterclockwise, with positions 7 to 3 as the moon increases light and positions 3 to 7 as the moon decreases light.
Therefore, we see that our 2 choices where we have a crescent is positions 6 and 8.
A. The amount of water. 50/50
From Doppler effect we have that the frequency observed for the relation between the velocities is equivalent to the frequency observed. That is mathematically,
Here,
Speed of sound in water 
The Dolphin swims directly away from the observer with a velocity 
Observed frequency of the clicks produced by the dolphin 
Replacing we have,
Therefore the frequency emitted by the dolphin is 2754.61Hz
